Your basically building a new equation with the two functions given to you.
(sqrt(3x + 7)) + (sqrt(3x - 7)) = 0
Then just open up the brackets and simplify further.
sqrt(3x + 7) + sqrt(3x - 7)= 0
Nothing to special really happened there, just removed the brackets. Now you move one of the radicals to the other side so you can square the whole equation.
sqrt(3x + 7) = - sqrt(3x - 7)
Then go ahead and square both sides to remove the radical.
3x + 7 = 3x - 7
Now if you kept trying to isolate x, you find that both sides will just cancel each other out and you are left with,
7 = -7
Since that statement isn't true your answer will be that there is no solution to this equation.
x ∈ Ø
4,3 hope it help the top is 4 and the bottom is 3
B , go with your first guest
126
Is the answer
Hope I helped
(x-h)^2 + (y-k)^2 = r^2
r=3
(x-h)^2 + (y-k)^2 = 3^2
the center lies on the y-axis --> h=0
x^2 + (y-k)^2 = 3^2 = 9
expand
x^2 + y^2 -2ky + k^2 = 9
x^2 + y^2 -2ky + (k^2 - 9) = 0
compare to general form
A=1 , B=1 and C =0
D= -2k and E=k^2 - 9
