The answer is 272 + 102 which equals 374yd^2
Answer:
The rate of change of the distance between the cars at that instant is 5.46 meters per second
Step-by-step explanation:
Speed of first car = 7 m/s
Speed of second car = 3 m/s
At instant, distance of first car from intersection = 5 meters
distance of second car from intersection = 12 meters
Therefore, we have
Distance between both cars at intant = √(12² + 5²) = 13 m
Rate of cahnge of distance is given by;
2ddd/dt = d(x² + y²)/dt = 2xdx/dt + 2ydy/dt
= 26dd/dt = 2×5×7 + 2×12×3 = 142
dd/dt = 142/26 = 5.46 m/s.
That is the rate of change of the distance between the cars at that instant = 5.46 meters per second.
This is set up as a proportion, so let’s cross multiply the values. When you do, you should get 21 = 6x. Now, divide each side by 6 to isolate the “x”. 21/6 is 3.5. x = 3.5. The unknown value is 3.5.
Answer:
y = -3x + 5
Step-by-step explanation:
(y2-y1)/(x2-x1)
Plug coordinates into that
Then plug one of the coordinates into y = -3x+b to get b
