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ziro4ka [17]
3 years ago
15

Solve the following equation by making an appropriate substitution. x Superscript negative 2 Baseline minus 2 x Superscript nega

tive 1 Baseline minus 15 equals 0 Make an appropriate substitution and rewrite the equation in quadratic form. Let uequals xz-1 x Superscript negative 1​, then the quadratic equation in u is u^2-2u-15(-5)(u+3) (u-5 )(u+3 ).
Mathematics
1 answer:
IrinaK [193]3 years ago
7 0

Answer:

  u^2-2u-15 = 0

Step-by-step explanation:

If you make the substitution ...

  u equals x Superscript negative 1 Baseline

then you can rewrite the equation as shown above.

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Which choice is equivalent to the quotient below shown here when x>0?
qwelly [4]

Answer:

Choice B is correct

Step-by-step explanation:

The given radical division can be expressed in the following form;

\frac{\sqrt{16x^{3} } }{\sqrt{8x} }

Using the properties of radical division, the expression can be expressed in the following form;

\sqrt{\frac{16x^{3} }{8x} }=\sqrt{2x^{2} }

Simplifying further yields;

\sqrt{2x^{2} }=\sqrt{2}*\sqrt{x^{2} }=x\sqrt{2}

Choice B is thus the correct alternative

5 0
3 years ago
Read 2 more answers
Sierra and Amy are selling cheesecakes for a school fundraiser. Customers can buy pecan
Tom [10]

Answer:

number 1 option

Step-by-step explanation:

Sierra

10p + 5s = 115

Amy

1p + 3s = 34

4 0
3 years ago
Jordan starts his day by doing his exercises. Jordan jumps rope for 10 minutes and lifts weights for 30 minutes. Jordan runs 10
romanna [79]

Answer:

35

Step-by-step explanation:

0.25 x 140 = 35

8 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
2 years ago
Do any of you get this question? Please help!
Alexxandr [17]
Honestly i just wanted to try this question since ive never seen it but i dont rlly know if i did it right at all

I equaled GH, HI, and GI together to get y

which i got y=-2

and what i got next i feel is off since

GH, HI, and GI all equaled -11

if you kind of know how to do the question maube you could correct me from there but otherwise dont take my word for it completely

4 0
3 years ago
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