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ziro4ka [17]
3 years ago
15

Solve the following equation by making an appropriate substitution. x Superscript negative 2 Baseline minus 2 x Superscript nega

tive 1 Baseline minus 15 equals 0 Make an appropriate substitution and rewrite the equation in quadratic form. Let uequals xz-1 x Superscript negative 1​, then the quadratic equation in u is u^2-2u-15(-5)(u+3) (u-5 )(u+3 ).
Mathematics
1 answer:
IrinaK [193]3 years ago
7 0

Answer:

  u^2-2u-15 = 0

Step-by-step explanation:

If you make the substitution ...

  u equals x Superscript negative 1 Baseline

then you can rewrite the equation as shown above.

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