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ziro4ka [17]
3 years ago
15

Solve the following equation by making an appropriate substitution. x Superscript negative 2 Baseline minus 2 x Superscript nega

tive 1 Baseline minus 15 equals 0 Make an appropriate substitution and rewrite the equation in quadratic form. Let uequals xz-1 x Superscript negative 1​, then the quadratic equation in u is u^2-2u-15(-5)(u+3) (u-5 )(u+3 ).
Mathematics
1 answer:
IrinaK [193]3 years ago
7 0

Answer:

  u^2-2u-15 = 0

Step-by-step explanation:

If you make the substitution ...

  u equals x Superscript negative 1 Baseline

then you can rewrite the equation as shown above.

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Luna at $50 when she got to the carnival after riding 12 rides she had twenty-six dollars left what was the price of which equat
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\frac{50 - 26}{12}  = x
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GIVING BRAINLIEST PLEASE HELP!!
barxatty [35]

Answer:

d.     hope I get it right I never got brainliest

Step-by-step explanation:

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2 years ago
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The pH of solution A is 2.4​, while the pH of solution B is 9.4.
pishuonlain [190]

Answer:

The answer to your question is below

Step-by-step explanation:

pH definition

                         pH = - log [H⁺]

a) For pH = 2.4, solution A

                       2.4 = -log[H⁺]

                      [H⁺] = antilog⁻².⁴

                      [H⁺] = 0.00398

  For pH = 9.4, solution B

                       [H⁺] = antilog⁻⁹.⁴

                       [H⁺] = 3.98 x 10⁻¹⁰

b) Divide hydrogen-ion concentration of solution A by hydrogen-ion concentration of solution B.

                             0.00398 / 3.98 x 10⁻¹⁰

                             10000000 times

c) By 7, because 7 is the number of zeros

3 0
3 years ago
Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in
Ronch [10]

The model in which the lateral surface meets the base at right angle is : Model 1.

<h3>What is a lateral surface?</h3>

The lateral surface of an object is all surfaces  of that object excluding its base and top.

Analysis:

To know the exact model, we check for the models in which their dimensions form a Pythagorean triplet otherwise a right-angled triangle.

For Pythagorean triplet, the square of the diagonal must be equal to the sum of squares of the other two sides.

Model 1

Diagonal = 50cm, radius = 14cm, lateral height = 48cm

(50)^{2} = (14)^{2} + (48)^{2}

2500 = 196 + 2304

2500 = 2500. Forms Pythagorean triplet

Model 2

Diagonal= 37cm, radius = 6cm  lateral height = 35cm

(37)^{2} = (35)^{2}+ (6)^{2}

1369 = 1225 +36

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Model 3

Diagonal = 60cm, radius = 20cm  lateral height = 40cm

(60)^{2} = (20)^{2} + (40)^{2}

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Model 4

Diagonal = 30cm, radius = 24cm, lateral height = 9cm

(30)^{2} = (24)^{2} + (9)^{2}

900 = 576 + 81

900 \neq 657

Therefore the lateral surface model 1 meets the base at right angle

In conclusion,  the lateral surface of model 1 meets the base at right angles as the dimensions form a right-angled triangle.

Learn more about Pythagorean triplet: brainly.com/question/20894813

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