Answer:
1) The reflection of a preimage (x, y) across the line y = x gives the image (y, x)
Therefore, the the coordinates of the points L, M, and N interchange to give an image of the triangle that is apparently rotated 90° clockwise, on the opposite quadrant and equidistant from the line y = x
2) Where the line segment drawn from point L to the reflecting line is horizontal, and the line segment drawn from point L to the reflecting line is horizontal, the two line segment will be of the same length and separated vertically separated vertically by a distance equal to the sum of the absolute values of the x and y coordinates of the point L
When the line segment from point L is drawn perpendicular to the reflecting line, the line segment from point L' drawn perpendicular to the reflecting line will meet the the perpendicular line segment at the same point of intersection of the line from the point L and the reflecting line
3) Yes
4) This is so because, reflection of a preimage unto an image is a form of rigid transformation, therefore, the effect of the transformation operation will be similar when each point is individually considered.
Step-by-step explanation:
What he's saying is that 7/8 of his ties + 4 ties = all of his ties.
7/8x + 4 = x
Thus, 4 is 1/8 of his ties.
4 = 1/8x
So you simply multiply 4 by 8 to get 32 ties.
32 = x
To check, plug 32 back into the original equation:
7/8(32) + 4 = (32)
28 + 4 = 32
It works!
Hope that helps.
Answer:
C) 846 in^2
Step-by-step explanation:
(15x48) + (21x3x2) = 846
Answer:
The answer is "5, 12, and 13".
Step-by-step explanation:
Please find the complete question in the attached file.
The right triangle is a triangle with only an angle of 90 degrees, as well as the go in the angle of 90 degrees, which is considered a hypotenuse.
The hypotenuse calculation square is equivalent to both the squared measures of the other two sides:
![C^2=A^2+B^2](https://tex.z-dn.net/?f=C%5E2%3DA%5E2%2BB%5E2)
And even those squares do verify the equation:
![169 = 144 + 25](https://tex.z-dn.net/?f=169%20%3D%20144%20%2B%2025)
So, it's a rectangular (right) triangle, with sides spanning ![5, 12, \ and \ 13.](https://tex.z-dn.net/?f=5%2C%2012%2C%20%5C%20and%20%5C%2013.)
Answer:All coordinate pairs that are in Quadrant I will have a positive x value and a positive y value. All coordinate pairs that are in Quadrant II will have a negative x value and a positive y value. All coordinate pairs that are in Quadrant III will have a negative x value and a negative y value.
Step-by-step explanation:ebob