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Kazeer [188]
3 years ago
6

In the figure to the right, ABCD is rectangle. Find the area of △ABC, if the area of △AOD is 10.

SAT
1 answer:
ololo11 [35]3 years ago
8 0
The correct answer is: Area of △ABC = 20

Explanation:
Since the area of △AOD = 10; therefore. the area of <span>△BOC is also 10.

Now:
The area of </span>△ABC = Area of △AOB + Area of <span>△BOC --- (1)

Since Area of </span>△AOB = \frac{1}{2} (Area of <span>△ABC) --- (2)

Plug (2) in (1):
(1) => Area of </span>△ABC = \frac{1}{2} (Area of △ABC) + 10
=> \frac{1}{2} (Area of △ABC) = 10
=> (Area of △ABC) = 20

<span>-i

</span>
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