In the figure below, ray was constructed starting from rays and . By using a compass D and G were marked equidistant from E on r

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3 years ago

13

In the figure below, ray was constructed starting from rays and . By using a compass D and G were marked equidistant from E on r

ays and . The compass was then used to locate a point F, distinct from E, so that F is equidistant from D and G. For all constructions defined by the above steps, the measures of ∠DEF and ∠GEF:

SAT

1 answer:

AURORKA [14] · Answer 1 · 2021-12-31T18:32:26+03:00

AURORKA [14]3 years ago

6 0

If you draw line segments DF and FG, you can show ΔDEF ≅ ΔGEF by SSS (side-side-side congruence). So, ∠DEF ≅ ∠GEF because corresponding parts of congruent triangles are congruent. Have fun with.. life lol