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Vinvika [58]
3 years ago
9

WILL GIVE A BRAINLIEST PLEASE HELP!!!

Mathematics
1 answer:
babymother [125]3 years ago
8 0
C. (–2, –2), (1, 7), (0, 4) is the correct answer. All three solutions match.
You might be interested in
Solve the inequalities -150x ≥ − 2,400 and -336 ≥ − 21y.
astra-53 [7]
Ok so easy peasy
remember that when divide or multiply by negative, reverse the inequality symbol example
2>3 times -1=
-2<-3 so

-150x<u>></u>-2400
divide both sides by -150
flip sign
<u />x<u><</u>16



-336<u>></u>-21y
divide both sides by -21
flip sign
16<u><</u>y

they seem to have the same solution

x=y<u>></u>16
4 0
3 years ago
Read 2 more answers
The picture Will pop up when you click on question
fiasKO [112]

Answer:

see below

Step-by-step explanation:

1. 10/16=5/6

2.14/63=2/9

3.6/14= 3/7

4.6/24= 1/3

5.7/70=1/10

6.5/10=1/2

7. 9/27= 1/3

8.6/72=1/12

9.6/27=1/3

10. 14/35= 2/5

11.12/24= 1/2

12.5/40=1/8

13.36/40=9/10

14.28/35=4/5

8 0
3 years ago
What does the d stand for?
Zielflug [23.3K]
If you're talking about PEMDAS it's Division. (Parenthesis., Exponents, Multiplication, Division, Subtraction just in case you forget)
4 0
3 years ago
I need help with problem
pychu [463]

Answer:

f(x)=4x(x-3)

Vertex=3/2, -9

Step-by-step explanation:

First, factorize it.

That is equal to 4x(x-3)

Therefore, x intercepts are 0 and 3, as  at least one of them need to be 0.

To find the vertex, first find the x of the vertex, which you can do by finding the average of the x intercepts, so it will be 3/2

Then, find the y, by making x in the original equation equal 3/2. This will give us -9 as the y.

The vertex will by 3/2, -9

4 0
2 years ago
Find the smallest positive integer solution to the following system of congruences: x = 0 (mod 5) x = 8 (mod 11) The solution is
igomit [66]

Answer:

The smallest positive integer solution to the given system of congruences is 30.

Step-by-step explanation:

The given system of congruences is

x=0(mod5)

x=8(mod11)

where, m and n are positive integers.

It means, if the number divided by 5, then remainder is 0 and if the same number is divided by 11, then the remainder is 8. It can be defined as

x=5m

x=11n+8

5m\cong 11n+8

Now, we can say that m>n because m and n are positive integers.

For n=1,

5m=11(1)+8=19

5m=19

19 is not divisible by 5 so m is not an integer for n=1.

For n=2,

5m=11(2)+8

5m=30

m=6

The value of m is 6 and the value of n is 2. So the smallest positive integer solution to the given system of congruences is

x=5(6)=30

Therefore the smallest positive integer solution to the given system of congruences is 30.

8 0
3 years ago
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