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Elena-2011 [213]
3 years ago
12

At noon the outside temperature was –5°F. By 4 p.m. the same day, the temperature had dropped 13°F. What was the outside tempera

ture at 4 p.m.? At 4 p.m. the outside temperature was °F.
Mathematics
2 answers:
Radda [10]3 years ago
7 0
The temperature turned to -18°F
-5-13=-18

MAXImum [283]3 years ago
5 0
<span>-5 + (-13) = -18ºF
</span><span>Good luck!</span>
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Answer:

x = \frac{5a-9}{19}

Step-by-step explanation:

Given

5(a - 2x) = 9(x + 1) ← distribute parenthesis on both sides

5a - 10x = 9x + 9 ( add 10x to both sides )

5a = 19x + 9 ( subtract 9 from both sides )

5a - 9 = 19x ( divide both sides by 19 )

\frac{5a-9}{19} = x

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Svetllana [295]

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Segment bisector = KL

IJ = 11⅓

Step-by-step explanation:

Segment KL cuts segment IJ into two equal parts. Therefore the segment bisector of IJ is said to be segment KL.

Length of IJ:

From the figure given, the bisector divided the IJ into two equal parts. 1 part is given as 5⅔, therefore, the 2 parts joined together will give us lenght of IJ.

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Write the following expression without using<br> negative exponents.
solmaris [256]

Option B:

$\frac{9{s^2} }{4 {m^3} {p^6}}

Solution:

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$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}

To write this expression without negative exponents:

$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}

Using exponent rule: a^{-b}=\frac{1}{a^b}

$m^{-3}=\frac{1}{m^3}

$p^{-6}=\frac{1}{p^6}

$s^{-2}=\frac{1}{s^2}

Substitute these in the expression.

$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}=\frac{9 \frac{1}{m^3}  \frac{1}{p^6} }{4 \frac{1}{s^2} }

Denominator of fraction in denominator goes to numerator.

Denominator of fraction in numerator goes to denominator.

Therefore, s^2 goes to numerator and m^3p^6 goes to denominator.

               $=\frac{9 \times {s^2}   }{4 {m^3}\times{p^6}}

              $=\frac{9{s^2} }{4 {m^3} {p^6}}

Option B is the correct answer.

$\frac{9 m^{-3} p^{-6}}{4 s^{-2}}=\frac{9{s^2} }{4 {m^3} {p^6}}

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