System of Equations
For the problem to solve we'll use the following variables:
x = number of the early bird tickets sold
y = number of the regular tickets sold
Haley sold a total of 20 tickets, thus:
x + y = 20 [1]
Early bird tickets cost $10 and regular tickets cost $15, thus the total money collected is:
10x + 15y = 225
Dividing by 5:
2x + 3y = 45 [2]
We have to solve the system of equations [1] and [2].
Multiply [1] by -2:
-2x - 2y = -40 [3]
Add [3] to [2]:
-2x - 2y +2x + 3y = -40 + 45
Simplifying:
y = 5
Substituting in [1]:
x + 5 = 20
Subtracting 5:
x = 20 - 5
x = 15
Solution: Hayley sold 15 early bird tickets and 5 regular-priced tickets
The order pair solution is (15,5)
Answer:
C. <em>3,300</em>
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Step-by-step explanation:
(2n2 + 4n + 4)(4n – 5)
= 8n^3 + 16n^2 +16n -10n^2 - 20n - 20
= 8n^3 +6n^2 -4n - 20
answer is d.
8n3 + 6n2 – 4n – 20
Answer:
5
Step-by-step explanation:
Answer:
-31
Step-by-step explanation:
(2×x) - (2×5) = (3×x) + (3×7)
2x-10 = 3x+21
2x-3x = 21+10
-x = 31
therefore, x = -31
