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Ksenya-84 [330]
3 years ago
10

tom determines the system of equations below has two solutions, one of which is located at the vertex of the parabola. equation

1: (x – 3)2 = y – 4 equation 2: y = -x bin order for this solution to be reasonable, which qualifications must be met?
Mathematics
1 answer:
stiks02 [169]3 years ago
8 0
( x -3 )² = y - 4
y = ( x - 3 )² + 4
One solution is located at the vertex: ( 3, 4 ).
y = - x + b
4 = - 3 + b
b = 7
( x - 3 )² = - x + 7 - 4
x² - 6 x + 9 = - x + 3
x² - 5 x + 6 = 0
x² - 2 x - 3 x + 6 = 0
x ( x - 2 ) - 3 ( x - 2 ) = 0
( x - 2 ) ( x - 3 ) = 0
x 1 = 2,  x 2 = 3
y 1 = 5,  y 2 = 4.
In order for this solution to be reasonable, the 2nd equation must be:
y = - x + 7

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Answer:

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P(A or B) = 0.71

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Step-by-step explanation:

b) Event B specifically rules out obesity, meaning, set A and set B have no elements in common.

In a normal probability question, event A or B usually means all the elements that are in either A or B and elements that are in the two sets.

But for this question, since, it has been made clear that there are no common elements in the two sets, event A or B is event that the person is overweight or obese. Option D.

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P(C) = 1 - P(A or B) = 1 - 0.71 = 0.29. Option A.

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Answer:

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