Question

If there are 19 plants with rough seeds in a population of 100, what is the allele frequency for smooth seeds?

Answer 1

Therefore 56% of the alleles in this population are smooth alleles, 44% of the alleles are rough alleles.

Answer 2

Answer:

$0.565\\Or\\56.5$%

Explanation:

Given,

Number of plants with rough seed $= 19$

Total number of plants $= 100$

Genotype frequency for "plant with rough seed" i.e $q^{2}$ $= \frac{19}{100} \\= 0.19$

So the allele frequency for "rough seed" $= \sqrt{q^{2} } \\= \sqrt{0.19} \\= 0.435$

As per Hardy weinberg equation, we know that sum of allele frequencies around the locus is equal to one .

Thus,

$p+q=1$

Substituting the value of q in above equation, we get -

$p+0.435=1\\p = 1-0.435\\p =0.565 \\Or 56.5$%

p represent the frequency of smooth seed.