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Leya [2.2K]
4 years ago
7

A box contains 15 cards. There are 5 red cards labeled 1, 2, 3, 4, and 5. There are 5 blue cards labeled 1, 2, 3, 4, and 5. Ther

e are 5 green cards labeled 1, 2, 3, 4, and 5. One card is drawn from the box.
What is the probability that it is a blue card with an even number or a red card with an odd number?

A.1/3


B.1


C.2/5


D.6/225
Mathematics
2 answers:
vichka [17]4 years ago
4 0
The answer is (A) 1/3.
aev [14]4 years ago
3 0
Should be A. 2 evenly numbered blue cards, plus 3 odd numbered red cards. Which makes 5/15, which then simplifies to 1/3.

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A=5b+8<br> Rearrange to make subject
Mumz [18]

AnswThe method is to separate the variable from everything else. That means getting the variable on one side of the equals sign and everything else on the other side. A=5B+8.

Subtract 8 from each side: A-8=5B.

Now divide each side by 5: (A-8)/5=B.

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Step-by-step explanation:

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3 years ago
Evaluate a+b for a =34 and b=-6
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Question

evaluate a+b for a =34 and b=-6

a + b =

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28

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3 years ago
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gayaneshka [121]
Is c that the answer
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guajiro [1.7K]

Answer:

x is 7, y is -1

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x+7y=0

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