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3 years ago

What is the average of the four smallest of integers ?

Mathematics

1 answer:

Elanso [62]3 years ago

6 0

This question is easier than it seems. If there are 9 consecutive integers with the mean being 16, then 16 must be the median. So just add four on top and four below 16 to give you your range of 9 values, 12-20. 12+13+14+15+16+17+18+19+20=144, 144/9=16. So the mean of the first four numbers is (12+13+14+15)/4= 13.5. If you check, 13.5 is also the median of these four numbers.

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A boy knows his height is 6 feet at the time of day when his shadow is 4 feet a trees shadow is 24 feet. What is the height of t

Schach [20]

The tree's height is 36 feet!

Work/explanation below:

1. The ratio of the boy's shadow to height is 4 : 6 or 1 : 1.5.

2. Plug the tree's shadow into the ratio and you have 24 : 24 X 1.5

3. 24 X 1.5 = 36.

Hope that helped!

:D®

5 0

3 years ago

What is - 3x - ( - 2 - 4x ) if x equals 5

m_a_m_a [10]

It would be 7 because -3 times 5

7 0

3 years ago

Find any 3 (x,y) pairs that are solutions for the equation 2x-5y=10 . Show your work

Alla [95]

Answer:

(0,-2), (5,0) and (10,2).

Step-by-step explanation:

Given equation is $2x-5y=10$ .

Now we need to find 3 pairs of solutions in (x,y) form for the given equation.

As $2x-5y=10$ is a linear equation so we are free to pick any number for x like x=0, 5, 10

Plug x=0 into $2x-5y=10$ , we get:

$2(0)-5y=10$

$0-5y=10$

$-5y=10$

$y=\frac{10}{-5}$

$y=-2$

Hence first solution is (0,-2)

We can repeat same process with x=5 and 10 to get the other solutions.

Hence final answer is (0,-2), (5,0) and (10,2).

5 0

3 years ago

Read 2 more answers

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

3 years ago

Suppose you begin with a pile of n stones and split this pile into n piles of one stone each by successively splitting a pile of

rodikova [14]

Start with five stones

7 0

3 years ago