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nataly862011 [7]
3 years ago
6

How do you factor k^2-k-56

Mathematics
2 answers:
klasskru [66]3 years ago
8 0
(k-8)(k+7) is how you factor is
saul85 [17]3 years ago
8 0
Use the factoring method
(k-8)(k+7)

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Help please!!!!!!!!!!!
julia-pushkina [17]

Answer:

f, it isnt doing anything as going up in units of water

Step-by-step explanation:

7 0
3 years ago
You want to ship textbooks from Florida. The textbooks are $60 each plus $150 shipping. Let x represent the number of textbooks
sertanlavr [38]

I am assuming the problem is asking you to find an equation repersenting the situation.


In this case, realize that 150 will be a constant, and 60 will be attached to the x variable, since the price of the textbooks changes based on how many textbooks there are.


Thus, the equation is:

60x + 150 = y


Our answer is 60x + 150 = y.

6 0
3 years ago
Find the sum <br> 1/2 (w-6)+ 1/4(w+12)
PolarNik [594]
Answer: 3/4w
Explanation:
1/2(w-6)+1/4(w+12)
= 1/2w-6/3 + 1/4w+12/4
= 1/2w-3 + 1/4w+12/4
= 1/2w +1/4w
= 2/2(1/2)w + 1/4w
= 2/4w+1/4w
=3/4w
5 0
4 years ago
Use substitution to solve the linear system of equations.
goblinko [34]

Answer:

(4, - 2 )

Step-by-step explanation:

Given the 2 equations

x = 4 → (1)

- y = \frac{1}{2} x → (2)

Substitute x = 4 into (2)

- y = \frac{1}{2} × 4 = 2 ( multiply both sides by - 1 )

y = - 2

Solution = (4, - 2 )

6 0
3 years ago
The interest rate r required to increase your investment p to the amount a in t years is found by . Find the interest rate r for
Dahasolnce [82]

Answer:

The interest rate was of 0.1173 = 11.73%.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

A = E + P

In this problem, we have that:

A = 10000, P = 8100, t = 2

So

A = E + P

10000 = E + 8100

E = 1900

So

1900 = 8100*I*2

I = \frac{1900}{8100*2}

I = 0.1173

The interest rate was of 0.1173 = 11.73%.

7 0
3 years ago
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