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Alex787 [66]
3 years ago
11

Find the midpoint of AB if a (-1,7) and B (11,-1)​

Mathematics
2 answers:
Nady [450]3 years ago
8 0

Answer:

  • (5, 3)

Step-by-step explanation:

<h3>Given </h3>
  • Points A(-1,7) and B (11,-1)​
<h3>To find</h3>
  • Midpoint of AB
<h3>Solution</h3>

<u>Using midpoint formula</u>

  • x = (-1 + 11)/2 = 10/2 = 5
  • y = (7 -1)/2 = 6/2 = 3

Midpoint is (5, 3)

Tomtit [17]3 years ago
5 0

Answer:

<h2>mid point = 5,  3</h2><h2></h2>

Step-by-step explanation:

A(-1, 7)   B(11, 1)

<u>use the midpoint formula:</u>

mid point = <u>(x₁ + x₂)</u> ,  <u>(y₁ + y₂)</u>

                        2              2

                = <u>(-1 + 11)</u> , <u>(7 - 1)</u>

                        2          2

mid point = 5,  3

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Help........ Again and thanks
Hunter-Best [27]

Answer:

x=3, y=1

Step-by-step explanation:

2x+y =7

3x-4y =5

Multiply the first equation by 4 so we can eliminate y

4(2x+y =7)

8x +4y =28

Add this to the second equation

8x +4y =28

3x-4y =5

----------------

11x = 33

Divide by 11

11x/11=33/11

x=3

Now we still need to find y

2x+y=7

2(3)+y =7

6+y=7

Subtract 6 from each side

6-6+y=7-6

y= 1

5 0
3 years ago
The equations : -3x+4y=-30− and 9x + 5 y = 39 intersect at the coordinate (h, k). What is the value of h?
Phantasy [73]

Answer:

h = 6

Step-by-step explanation:

Given the 2 equations

- 3x + 4y = - 30 → (1)

9x + 5y = 39 → (2)

We require the value of the x- coordinate at the point of intersection, thus require to eliminate the y- term from the equations

Multiply (1) by 5 and (2) by - 4

- 15x + 20y = - 150 → (3)

- 36x - 20y = - 156 → (4)

Add (3) and (4) term by term thus eliminating y

- 51x = - 306 ( divide both sides by - 51 )

x = h = 6

5 0
3 years ago
Which ordered pair is a solution to the inequality?<br><br> Help please!!
Murrr4er [49]

Choice A is the answer which is the point (1,-1)

=========================================

How I got this answer:

Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.

-------------

checking choice A

plug in (x,y) = (1,-1)

y - 2x \le -3

-1 - 2(1) \le -3

-3 \le -3

This is true because -3 is equal to itself. So this is the answer.

-------------

checking choice B

plug in (x,y) = (2,4)

y - 2x \le -3

4 - 2(2) \le -3

0 \le -3

This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.

-------------

checking choice C

plug in (x,y) = (-2,3)

y - 2x \le -3

3 - 2(-2) \le -3

7 \le -3

This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.

-------------

checking choice D

plug in (x,y) = (3,4)

y - 2x \le -3

4 - 2(3) \le -3

-2 \le -3

This is false because -2 is not to the left of -3, nor is -2 equal to -3. We can cross this off the list.


4 0
3 years ago
The half-life of caffeine in a person’s bloodstream is about 6 hours. If a person’s bloodstream contains 80 milligrams of caffei
Luda [366]
To calculate the remaining caffeine, we use the radioactive decay formula which is expressed as An = Aoe^-kt where An is the amount left after t time, Ao is the initial amount and k is a constant we can calculate from the half-life information. We do as follows:
 at half-life,
ln 1/2 = -k(6)
k = 0.12/hr

An = 80e^-0.12(14)
An = 15.87 mg
5 0
4 years ago
54 divided by 1200 remainder as a fraction quick
BaLLatris [955]

22  1111111 /5000000

7 0
3 years ago
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