0.067318 to 2 significant figures

Mariulka [41]

Answer:

17

Step-by-step explanation:

The quadratic function f (x) has a turning point at (5.-8). If 8(x)= f(x+7)-3. then at which of the following ... If f(x) is an odd. one-to-one function with f (5) = -2 then which point must lie on the graph of its ... Solve the equation f(x) = g(x) for all values of x. ... (3) (-4.10). 1. 2.64x+4 +y2-10y+25 =-12+4+25. (x+2)(x+2) +ly-sly-5)= 17.

6 0

3 years ago

Given that tan θ ≈ −0.087, where 3 2 π < θ < 2 , π find the values of sin θ and cos θ.

elena-s [515]

Answer:

sin θ ≈ -0.08667
cos θ ≈ 0.99624

Step-by-step explanation:

Straightforward use of the inverse tangent function of a calculator will tell you θ ≈ -0.08678 radians. This is an angle in the 4th quadrant, where your restriction on θ places it. (To comply with the restriction, you would need to consider the angle value to be 2π-0.08678 radians. The trig values for this angle are the same as the trig values for -0.08678 radians.)

Likewise, straightforward use of the calculator to find the other function values gives ...

sin(-0.08678 radians) ≈ -0.08667

cos(-0.08678 radians) ≈ 0.99624

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Note on inverse tangent

Depending on the mode setting of your calculator, the arctan or tan⁻¹ function may give you a value in degrees, not radians. That doesn't matter for this problem. sin(arctan(-0.087)) is the same whether the angle is degrees or radians, as long as you don't change the mode in the middle of the computation.

We have shown radians in the above answer because the restriction on the angle is written in terms of radians.

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Alternate solution

The relationship between tan and sin and cos in the 4th quadrant is ...

$\cos{\theta}=\dfrac{1}{\sqrt{1+\tan^2{\theta}}}\\\\\sin{\theta}=\dfrac{\tan{\theta}}{\sqrt{1+\tan^2{\theta}}}$