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alexandr1967 [171]
3 years ago
9

What is correct?

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0
4 °C

i just googled it XD. source: https://www.google.com/search?q=the+density+of+water+is+maximum+at+which+temperature&oq=the+density+of+water+is+maximum+at+which+temperature&aqs=chrome..69i57.699j0j4&client=ms-android-samsung&sourceid=chrome-mobile&ie=UTF-8
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12ax^{2} -15ab-16a+20b[/tex]
irina1246 [14]

Answer:

12 a x^ 2 -15 a b-16 a

5 0
3 years ago
Label 1/4 on the number line. Label 1/2 on the number line .
KIM [24]

Answer:

it goes 0 then 1/4 in the first notch 1/2 in the second notch 3/4 in the third notch then the number 1 on the fourth

Step-by-step explanation:

Hope that helps.

5 0
3 years ago
Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!! I don't understand it!
katrin2010 [14]

Answer:

  13.98 in²

Step-by-step explanation:

I don't understand it, either.

Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.

__

The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.

The area of a segment is given by the formula ...

  A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.

Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...

  A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²

Rounded to hundredths, this is ...

  ≈ 13.98 in²

3 0
3 years ago
Please helppppppppppppp
Leona [35]
The x would equal 0 and the y would equal 3
6 0
2 years ago
34=−2t can u help me
IrinaK [193]
34/2= -t => 17= -t => t= -17
4 0
3 years ago
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