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tatuchka [14]
3 years ago
5

a person can pay $21 for a membership to the history for just $1 per visit what is the maximum number of this has a number of th

e history be seen you can make of a total cost of $30 ​
Mathematics
1 answer:
yarga [219]3 years ago
4 0

Answer:

Your question doesnt make sense

Step-by-step explanation:

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Help please. no clue what I'm doing​
Ugo [173]

Answer:

Option second!!!!!!!

4 0
3 years ago
If travel at a rate of 45 mph how many minutes will it take you to travel 1 mile
xz_007 [3.2K]
Every minute you would travel .75 miles, but divide that by 3 and you get 1 minute and 33 seconds.

4 0
3 years ago
QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
2 years ago
Consider the inequality -5(x+7)<-10 write inequality representing a solution for x
dedylja [7]
Perform indicated multiplication on left side first...

-5x-35<-10  add 35 to both sides

-5x<25  divide both sides by -5 (you must reverse sign because of division by a negative value too!)

x>5  or if you prefer...

x=(5, +oo)
6 0
3 years ago
Unit 6 homework 2 need help
kodGreya [7K]

∆PQR and ∆SQT are similar, so corresponding sides occur in fixed ratios with one another. This means

SQ / PQ = ST / PR

Solve for x :

8 / ((x + 5) + 8) = (x - 9) / 21

8 / (x + 13) = (x - 9) / 21

168 = (x - 9) (x + 13)

168 = x² + 4x - 117

x² + 4x - 285 = 0

(x + 19) (x - 15) = 0

⇒   x = -19   or   x = 15

But x can't be smaller than 9, otherwise ST = x - 9 would be a negative length. So x = 15.

8 0
2 years ago
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