4. SOLVE FOR X:
Using the Alternate Interior Angles Theorem, we know that the 67 degree angle is congruent with the (12x - 5) degree angle. With this information, all I have to do is set the two equal to each other and solve for x.
67 = 12x - 5
67 + 5 = 12x - 5 + 5
72/12 = 12x/12
6 = x
x = 6
SOLVE FOR Y:
Using the Vertical Angles theorem, we know that angle y must be congruent to the 67 degree angle.
y = 67 degrees.
5. SOLVE FOR Y:
Alternate exterior angles: 6(x - 12) = 120
6x - 72 + 72 = 120 + 72
6x/6 = 192/6
x = 32
SOLVE FOR Y:
6((32) - 12) + y = 180
192 - 72 + y = 180
120 + y - 120 = 180 - 120
y = 60
Im not sure why you said ur wrong b/c i got the same answer
f(x) = -15+ 7
f(x) = -8
Answer:
6.8
Step-by-step explanation:
a^2 + b^2 = c^2
6.6^2 + b^2 = 9.5^2
43.56 + b^2 = 90.25
b^2 = 90.25 - 43.56
b^2 = 46.69
(take square root of both sides)
b = 6.8
Answer:
the object will attain maximum height at 3.5 seconds.
Step-by-step explanation:
The height of the object (in feet), h, above the ground t seconds after it is fired is given by h(t)=−16t2+112t+128.
128 represents 128 feet above the ground and this is the height from which the object was fired.
The given equation is a quadratic equation and plotting of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.
The vertex of the parabola is calculated as follows,
Vertex = -b/2a
From the equation,
a = -16
b = 112
Vertex = - - 112/32= 3.5
So the object will attain maximum height at 3.5 seconds.
