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Vadim26 [7]
3 years ago
6

Which network topology requires terminators at the ends of the backbone cable?

Computers and Technology
1 answer:
navik [9.2K]3 years ago
7 0
In the 1980's, <span>10BASE2 ethernet networks required termination with a 50ohm resistor at either end. The computers were all connected to this long cable with T-junctions. This is a bus topology.</span>
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A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter
trapecia [35]

Answer:

5 Letters

Explanation:

So we need 12 distinct codes made of a single letter or a pair of letters.

What would be the least number of letters?

Lets try with 3 letters A, B and C

The possible combinations are: A, B, C, AB, AC, BC

These are 6 codes and we need 12 so lets try more A, B, C and D

The possible combinations are: A, B, C, D, AB, AC, AD, BC, BD, CD

These are 10 codes and we need 12 so lets try more A, B, C, D and E

The possible combinations are:

A, B, C, D, E, AB, AC, AD, AE, BC, BD, BE, CD, CE, DE

Finally we got 15 distinct codes which are more than 12 so the least number of letters needed are 5.

Using formula:

Four letters = 4C1 + 4C2 = 4 + 6 = 10

Five letters = 5C1 + 5C2 = 5 + 10 = 15

5 0
2 years ago
What are the two ways to use the help menu
neonofarm [45]
What help menu are you talking about?
6 0
3 years ago
Read 2 more answers
Write the following program in C++ to print:
Alenkinab [10]
1.
#include <iostream>#include <string>
using namespace std;
int main(){    string chars; // This is where we will put our @ signs and print them    for(int x=0;x < 5; x++){
        chars = chars + '@'; // This will concatenate an @ sign at the end of the variable        cout << chars << "\n";    }}

2.
#include <iostream>#include <string>
using namespace std;
int main(){    string name; // Our variable to store the name    cout << "What is your name? \n"; // Asks the user for their name    cin >> name;    cout << "\nWell, hello " << name << "!";}

3.
#include <iostream>#include <string>
using namespace std;
int main(){    int number; // Our variable    cout << "Enter a number\n"; // Asks for a number    cin >> number;    cout << "You entered " << number << "%!";}

4.
#include <iostream>#include <string>
using namespace std;
int main(){    int number; // Our variable    cout << "Enter a number\n";    cin >> number;
    int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient    if (check == 0) {        cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even"    } else {        cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd"    }}

5.
#include <iostream>#include <string>
using namespace std;
int main(){    float r; // Our variable    cout << "Enter a radius\n";    cin >> r;    if (r < 0){        cout << "Lol. No."; // If the radius is less than zero print out that message    }    float circumference=2*3.14*r;    float area=r*r*3.14;    cout << "\n\n Circumference of circle: " << circumference;    cout << "\n Area of circle: " << area;}
4 0
3 years ago
Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. T
kompoz [17]

Answer:

I can't read that pls reformat, or take picture.

Explanation:

3 0
2 years ago
At one college, the tuition for a full-time student is $6,000 per semester. It has been announced that the tuition will increase
Alina [70]

Answer:

  1. var projected_fee = 6000;  
  2. for(var i = 1; i <= 5; i++){
  3.    projected_fee = projected_fee * 0.02 + projected_fee;
  4.    console.log("$" + projected_fee.toFixed(2));
  5. }

Explanation:

Firstly, create a variable, projected_fee, and set the initial tuition fee value to it (Line 1).

Next, user a for loop that run for 5 times to repeatedly calculate the projected_fee based on 2 percent of increment rate (Line 4) and display the projected fee to console terminal (Line 5). The output should be

$6120.00

$6242.40

$6367.25

$6494.59

$6624.48

8 0
2 years ago
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