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Ne4ueva [31]
3 years ago
14

A file named data.txt contains an unknown number of lines, each consisting of a single integer. Write some code that creates two

files, dataplus.txt and dataminus.txt, and copies all the lines of data1.txt that have positive integers to dataplus.txt, and all the lines of data1.txt that have negative integers to dataminus.txt. Zeros are not copied anywhere.
Computers and Technology
2 answers:
slavikrds [6]3 years ago
6 0

Answer:

#section 1

data = open('data.txt', 'r')

num = (data.read())

num = num.split()

data.close()

#section 2  

for x in num:

   x = int(x)

   if x < 0:

       minus = open('dataminus.txt', 'a')

       minus.write(str(x) + ' ')

       minus.close()

   elif x > 0:

       plus = open('dataplus.txt', 'a')

       plus.write(str(x)+' ')

       plus.close()

Explanation:

#section 1

A file data.txt containing an unknown number of lines each containing a single integer is opened.

The data is read from it and split to form a list from which the code will iterate over with a FOR loop and some conditional statements will be used to determine if the number is positive or negative.

#section 2

In this section two new files are created/ opened dataplus.txt and dataminus.txt and all the positive integers are stored in the dataplus.txt and the negative integers in the dataminus.txt.

The IF statement and elif statement used ensures that zero(0) is not captured ensuring that the code fulfills all the requirements in your question.

Damm [24]3 years ago
3 0

Answer:

I am doing it with python.

Explanation:

nums = '9 -8 -7 -6 -5 -4 -2 0 1 5 9 6 7 4'

myfile = open('data.txt', 'w')

myfile.write(nums)

myfile.close()

myfile = open('data.txt', 'r')

num1 = (myfile.read())

num1 = num1.split()

print(num1)

print(type(num1))

for x in num1:

   x = int(x)

   if x < 0:

       minus = open('dataminus.txt', 'a')

       minus.write(str(x) + ' ')

       minus.close()

   elif x>= 0:

       plus = open('dataplus.txt', 'a')

       plus.write(str(x)+' ')

       plus.close()

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import java.util.Scanner;

public class ss11{

       public static void main (String[]args) {

             Scanner keyboard = new Scanner (System.in)

             String a1, a2, a3, a4, a5;

              int i1, i2, i3, i4, i5;

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               a1= keyboard.next();

               a2= a1.substring(0,1);

               a3= a1.substring(1,2);

               a4= a1.substring(2,3);

               a5= a1.substring(3,4);

                i1 = Integer.parseInt(a2);

                i2 = Integer.parseInt(a3);

                i3 = Integer.parseInt(a4);

                i4 = Integer.parseInt(a5);

                i1= i1 * 8;

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                i4= i1 * 1;

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Explanation:

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Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
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Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

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