What is the radius of a circle with an area of 32.1 square feet?

Geography

2 answers:

tamaranim1 [39]3 years ago

7 0

The square feet area of 32.1 is going to be 3.2 feet.

BigorU [14]3 years ago

3 0

The correct answer is 3.2

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Telescope A has a diameter of 1.00 meters, while telescope B’s diameter is 9.00 meters. What is the ratio of the angular resolut

Mama L [17]

Answer:

the ratio of resolution will be $\frac{1}{9}$

Explanation:

We have given the diameter of Telescope A is 1 meter

And diameter of telescope B is 6 meter

We know that resolution of telescope is inversely proportional to diameter of the telescope

So $resolution\ \propto\frac{1}{diameter}$

We have to find the ratio of resolution of B to A

So $\frac{\Delta \Theta _B}{\Delta \Theta _A}=\frac{D_A}{D_B}=\frac{1}{9}$

So the ratio of resolution will be $\frac{1}{9}$

3 0

3 years ago

A satellite orbiting earth has a tangential velocity of 5000 m/s. earth’s mass is kg and its radius is m. which is the distance

inessss [21]

The distance of the satellite form the earth is:
9,608,000 m (Option C) in Standard form, this is written as 9.6 x 10 $^{6}$ .

<h3>What is an Orbiting Satellite?</h3>

An Orbiting Satellite is a satellite that goes around the earth in an elliptical path known as an orbit.

To calculate the distance of the satellite from the earth we must equalize the force of Gravity to Centripetal Force given that these are the two forces that are at play here.

Step 1:

Equation that equalizes Gravity to Centripetality is:

G = mM/r² = m(v²/r)

Note that G = 6.67 x 10 $^{-11}$ (This is a gravitational constant.)

m is the Mass of the Satellite

M is Mass of the Earth

r is the distance of the satellite from the center of the earth

v is the satellites tangential velocity

Step 2 - Rearrange the formula and substitute the numbers above to get r

r = G (m/v²) = (6.67 x 10 $^{-11}$ ) (6 x10 $^{24}$ /5000²) =

= 1.6 x 10 $^{7}$ m

Recall that form our postulation above, this is the satellites distance form the center of the earth.

To get it's distance form the earth's surface, we must know remove the value of the radius of the earth from the calculation. Where radius of the earth is given a r'

Hence,

r' = r - R = 1.6 x 10 $^{7}$ m - 6.4 x 10 $^{6}$ m

= 9.6 x $10^{6}$ m or 9,608,000 m