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3 years ago

13

why is a single system of measurement (the metric system) important to use in the scientific community? Think of at least one ex

ample why they need the standard measurement.

1 answer:

Tems11 [23]3 years ago

7 0

Answer:

to make the uniformity in the world measurement

Explanation:

means everyone could measure 1 kg in world 1 kg only in any part of world so it is bought in action of standard measurement

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What is the midpoint and distance of <br> ( -6 , 5), (-1 , -2)

Taya2010 [7]

The midpoint of given points is $\left(\frac{-7}{2}, \frac{3}{2}\right)$

The distance between the given points is 8.6023 units

<em><u>Solution:</u></em>

Given that two points are (-6, 5) and (-1, -2)

We have to find the midpoint and distance

<em><u>The midpoint of two given points is given as:</u></em>

$m(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

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$x_{1}=-6 ; x_{2}=-1 ; y_{1}=5 ; y_{2}=-2$

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Thus the midpoint of given points is $\left(\frac{-7}{2}, \frac{3}{2}\right)$

<u><em>Distance between given points:</em></u>

The formula for distance is given as:

$D=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

<u><em>Substituting the values in formula, we get</em></u>

$\begin{aligned}&D=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}\\\\&D=\sqrt{(-1-(-6))^{2}+(-2-5)^{2}}\\\\&D=\sqrt{5^{2}+(-2-5)^{2}}\\\\&D=\sqrt{25+49}=\sqrt{74}\end{aligned}$

D = 8.6023 units

Thus the distance between the given points is 8.6023 units

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