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notka56 [123]
3 years ago
6

Can you help me Solve this and show the stepd

Mathematics
1 answer:
NikAS [45]3 years ago
6 0
130-51 is 79 this is it D
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What is the radius of sphere with a surface area of 100cm2
Novosadov [1.4K]

Answer:

10cm2

Step-by-step explanation:

5 0
3 years ago
You drive 75 miles and use 3 gallons of gas, at the same ratio, how may miles can you drive with 12 gallons of gas?
umka2103 [35]

When you say "at the same ratio", you mean that you consume the same amount of gas for the same amount of miles.

We know that everytime you drive 75 miles, you use 3 gallons of gas.

Since 12 gallons of gas is four times 3 gallons of gas, if the ratio remains the same, you can drive four times the distance:

You drive 75 miles, and use 3 gallons.

You drive 75 more miles (so you are at 75+75 = 150 miles) and use 3 more gallons, so you use 3+3 = 6 gallons.

You drive 75 more miles (so you are at 150+75 = 225 miles) and use 3 more gallons, so you use 6+3 = 9 gallons.

You drive 75 more miles (so you are at 225+75 = 300 miles) and use 3 more gallons, so you use 9+3 = 12 gallons, and you're done.

4 0
3 years ago
HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
-20x2 + x + 12<br> Factor
Pavel [41]

Answer:

[x-3] [x+4]

Step-by-step explanation:

You look to see if you spot the appropriate factors strait away. If you can not immediately determine them you have to consider all of the potential ones and reason out which ones work.

7 0
3 years ago
Write an equation in point-slope form for the line through the given point with the given slope.
Lilit [14]

The correct answer is D) y + 1 = 4/3(x - 9)

In order to find this, simply take the point and the slope and plug into the base form of point-slope form.

y - y1 = m(x - x1)

Use the slope for m and the point for (x1, y1)

y + 1 = 4/3(x - 9)

7 0
3 years ago
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