Answer:
if it helps please mark brainliest!
Step-by-step explanation:
essays= x
quizzes=y
2x=60
x=30 1 essay per 30 days
4y=40
y=10 1 quiz every 10 days
120/30=4
120/10= 12
so 4 essays and 12 quizzes in 120 days
if it helps please mark brainliest!
Answer:
E: None of the above
Step-by-step explanation:
Hello!
The objective is to find out how much time it takes people to commute to work.
Two samples where taken and two hypothesis tests where made:
One:
Sample mean 71 min; p-value: 0.03
Two:
Sample mean 72 min; p-value: 0.06
You have to choose from the options, a possible pair of hypotheses used for these two tests.
The parameter of the study is the population mean μ.
In the statistic hypotheses, the parameters are given either a known population value or a suspected value. So all options including sample values are wrong.
As said before the objective of the survey is to "determine how much time people spend commuting to work" in other words, whether or not the population mean is equal to a certain value.
H₀: μ = μ₀
H₁: μ = μ₀
Where μ₀ represents the theoretical value of the population mean. As you can say the hypotheses pair is two-tailed, not one-tailed.
Then the correct answer is E: None of the above
I hope this helps!
Well, since 3/15 can be simplified to 1/5 by dividing the top and the bottom by 3, you would just need to find the decimal of 1/5 which is much more commonly recognized. it's .2 (becasue 1/10 would be .1 and 1/5=2/10 so .1x2=.2)
3/7 = 0.43 (approx.)
4/9 = 0.44 (approx.)
Hence, 4/9 is bigger.
Answer: 0.9088
Step-by-step explanation:
Given : 
Let x be a random available that represents the proportion of students that reads below grade level .
Using 
, for x= 0.36 , we have
Using standard normal z-value table,
P-value 
[Rounded yo the nearest 4 decimal places.]
Hence, the probability that a second sample would be selected with a proportion less than 0.36 = 0.9088
