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uysha [10]
3 years ago
5

What is the median of 114,90,83,101,97,142,117,87,72

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer: 97

Step-by-step explanation:

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PLEASE HELP!!! Given the functions, f(x) = 6x + 2 and g(x) = x - 7, perform the indicated operation. When applicable, state the
Brums [2.3K]

Answer:

The domain restriction for (f/g)(x) is x=7

Step-by-step explanation:

we have

f(x)=6x+2

g(x)=x-7

so

(f/g)(x)=\frac{6x+2}{x-7}

Remember that

the denominator can not be equal to zero

so

Find the domain restriction

x-7=0

x=7

therefore

The domain is all real numbers except the number 7

(-∞,7)∪(7,∞)

4 0
3 years ago
Read 2 more answers
4y-4=_____<br> 4(y+1)=___<br> 2+4y=____
34kurt
If they are looking to have them all simplified, this is how they should look. 

4y - 4
4y + 4
4y + 1
3 0
3 years ago
(25 points)
Licemer1 [7]
Here, y = -15 with x = -20
LCM of 15 & 20 is 60, so divide 15 & 20 from 60, 
60/15 = 4 & 60/20 = 3

Now, multiply the results with intial values, 
4y = 3x
y = 3/4 x

When y = 12, 
x = 12 * 4/3
x = 48 / 3
x = 16

In short, Your Answer would be 16

Hope this helps!

8 0
3 years ago
A farm had 480 acres more wheat than corn. After the farmers collected 80% of the wheat and 25% of the corn, the area of the whe
SVEN [57.7K]
A farm had 480 acres more wheat than corn. Let use "W" to represent the Wheat and let use "C" to represent the corn. Hence, we have below:
W=C+480

The farmers collected 80% of the wheat and 25% of the corn and the area of the wheat is 300 acres less than the area of the corn:
W-0.8W=C-0.25C+300
0.2W=0.75C+300
We have two equations, two unknowns:
0.2(C+480)=0.75C+300
0.2C+96=0.75C+300
0.55C=294
C=534.55
6 0
2 years ago
Read 2 more answers
16. Let W be the set of all vectors in R3 of the form a+2b b -3a Find a basis for Wand state the dimension of W.
Yuki888 [10]

Answer:

W=\{\left[\begin{array}{ccc}a+2b\\b\\-3a\end{array}\right]: a,b\in\mathbb{R} \}

Observe that if the vector x=\left[\begin{array}{ccc}x\\y\\z\end{array}\right] is in W then it satisfies:

\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]

This means that each vector in W can be expressed as a linear combination of the vectors \left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]

Also we can see that those vectors are linear independent. Then the set

\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\} is a basis for W and the dimension of W is 2.

7 0
2 years ago
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