<h2>Answer:</h2>
8.75 feet
<h2>
Step by step:</h2>
Given that a 12 foot ladder leans against a building seven feet above the ground.
By using trigonometry ratio, the angle between the ladder and the ground will be
SinØ = opposite/ hypothenus
SinØ = 7 / 12
SinØ = 0.58333
Ø = Sin^-1(0.58333)
Ø = 35.69 degree
At what height would an 15 foot ladder touch the building if both ladders form the same angle with the ground?
Using the same trigonometric ratios
SinØ = opposite/hypothenus
Sin 35.69 = opposite/ 15
Cross multiply
Opposite = 15 × sin 35.69
Opposite = 8.75 feet
Therefore, the ladder will touch the building if both ladders form the same angle with the ground at height 8.75 feet.
Answer: 8
Step-by-step explanation:
80 is in the tens place. second digit left of decimal
Answer:
2.6 meters per seconds squared
Step-by-step explanation:
We can use the formula F = MA to solve this problem.
F is the force (in Newtons)
M is the mass (in Kgs)
A is the acceleration in m/s^2
The force (F) is given as 2.4 newtons and mass (M) is given as 0.94 kgs, so we substitute into the formula and solve for acceleration (A):
F = MA
2.4 = 0.94(A)
A= 2.4/0.94 = 2.55 m/s^2
<em>rounding to nearest tenth, we have </em><em>acceleration = 2.6 m/s^2</em>
Answer:
The coordinates of the point P is 14.
Step-by-step explanation:
Let point A is at 8 and B is at 16.
P is the point where the line segment in the ratio 3 : 1.
This is also where P is 
rds the distance from A to B
The total distance is |16 - 8| = 8
The distance between point AB is 8 units.
of 8 is 6.
So, the point P is 6 units from A
.
8 + 6 = 14
P is at 14
Hence, the coordinates of the point P is 14.
This also works if you go 1/3 from B.
-8 is 4 from -4 which is 1/3 of 12.
The first one is x=-1
The second one is b=1
The third one is t=3
