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rjkz [21]
3 years ago
13

Jill measured the length of her eraser. She wrote 5 on her paper without the unit. Which metric unit of measure should Jill incl

ude?
Mathematics
2 answers:
Nookie1986 [14]3 years ago
8 0
Jill should include centimeters as part of her answer. 5 centimeters.
Drupady [299]3 years ago
4 0
It depnds on how long the eraser is. it could be 5 millimeters or 5 kilometers. It may be centimeters or decimeters. i'd go with centimeters
hoped i helped
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Type the correct answer in each box. Use numerals instead of words.
Colt1911 [192]

One twentieth is 5%, so the total cost is

f(c) = 1.05 c

The domain is [80, 180]

For Albert to afford the shoes

f(c) \le 105 + 42

1.05 c \le 147

c \le 147/1.05 = 140

That's the maximum so he can afford shoes with preshipping prices in the domain

[80, 140]

7 0
3 years ago
The temperature one morning in Shasta was LaTeX: -12^\circ F− 12 ∘ F. By the afternoon, the temperature had risen LaTeX: 8^\circ
Vlad [161]

Answer:

The Temperature in the afternoon was -4\° F.

Step-by-step explanation:

Given:

Temperature in the morning = -12\° F

Rise in temperature = 8\° F

We need to find the temperature in the afternoon.

Solution:

Now we know that;

temperature in the afternoon is equal to Temperature in the morning plus Rise in temperature in afternoon.

framing in equation form we get;

temperature in the afternoon = -12\° F+8\° F=-4\° F

Hence the Temperature in the afternoon was -4\° F.

3 0
3 years ago
100 POINTS!!!!!!!!!!! ( I NEED FAST ANSWERS ) At a cost of $200, your club bought 175 frisbees to sell at the pep rally.
ivann1987 [24]

Answer:

it would be 675

Step-by-step explanation:

you would of earned 875 by times 175 times 2 then you subtract  200 for the cost

8 0
4 years ago
F = Gm^2/r^2 solve for g
TEA [102]
F=\frac{Gm^{2}}{r^{2}} \rightarrow Fr^{2}=Gm^{2} \rightarrow G=\frac{Fr^{2}}{m^{2}}
5 0
3 years ago
Read 2 more answers
Eureka Math : 5 ÷ 1/3= ____. There are ___ thirds in 1 whole. There are ___ thirds in 5 wholes. If 5 is 1/3, what is the whole?
oksian1 [2.3K]

Let me edit your question to simplify it.

Eureka Math :

A)5 ÷ 1/3= ____.

B) There are ___ thirds in 1 whole.

C) There are ___ thirds in 5 wholes.

D) If 5 of 1/3, what is the whole? ___

E) 3 ÷1/5= ____ .

F) There are ___ fifths in 1 whole.

G) There are ___ fifths in 3 wholes.

H) If 3 of 1/5, what is the whole?___

Answer:

A) 15

B) three thirds

C) 15 wholes

D) whole is 2

E) 15

F) five fifths

G) 15 fifths

H) whole is 1

Step-by-step explanation:

A)

  • 5÷\frac{1}{3} =5*\frac{3}{1}
  • 5÷\frac{1}{3}=15

<u>Third:</u>

  • third means \frac{1}{3}<u> </u>

B)

  • To make 1 whole from thirds, we need three thirds i.e. \frac{1}{3}+\frac{1}{3}+\frac{1}{3}=\frac{3}{3}=1\ Whole

C)

  • In 1 whole there are three thirds, so in 5 wholes there are 5*3=15 wholes.

D)

  • In 5\ of\ \frac{1}{3}=5*\frac{1}{3} =\frac{5}{3}
  • \frac{5}{3}=1.6
  • The whole of 1.6 or \frac{5}{3} is 2 (rounding 1.6 to 2)

E)

  • 3÷\frac{1}{5}=3*5=15

<u>Fifth:</u> means \frac{1}{5}

F)

  • To make 1 whole of fifths we need five fifths i.e. \frac{1}{5} +\frac{1}{5} +\frac{1}{5} +\frac{1}{5} +\frac{1}{5}=\frac{1+1+1+1+1}{5}=\frac{5}{5}=1

G)

  • In 1 whole we have 5 fifths, so in 3 wholes we have 3*5=15 fifths

H)

  • 3\ of\ \frac{1}{5}=3*\frac{1}{5}=\frac{3}{5}=0.6
  • rounding 0.6 equals to 1
  • thus whole is 1.

 

3 0
3 years ago
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