Answer:
P(B) = 8/12
P(R | B) = 4/11
P(B ∩ R) = 8/33
The probability that the first ball chosen is black and the second ball chosen is red is about 24 percent.
Step-by-step explanation:
I just got it right on edge 2020. Good luck with school!!
I have the same question on a test I'm taking thanks
I believe the answer is....
For solving for a
a-7= 3(b+2) ———> distribute 3(b+2)
a-7= 3b+6 ———-> add 7 on both sides
a-7= 3b+6
a+7= 3b +7 ———-> the 7’s cancel out so you’re left with....
a = 3b + 13 (That’s your answer)
Hope that helped :3
