Answer:
The answer is A4B₁₆ = 2635₁₀ = 101001001011₂
Explanation:
To convert from hexadecimal base system to binary base system, first you can do an intermediate conversion from hexadecimal to decimal using this formula:
where position of the x₁ is the rightmost digit of the number and the equivalents hexadecimal numbers to decimal:
- A = 10.
- B = 11.
- C = 12.
- D = 13.
- E = 14.
- F = 15.
A4B₁₆ = A*16²+4*16¹+B*16⁰ = 2560 + 64 + 11 = 2635₁₀
Now, you have the number transformed from hexadecimal to decimal. To convert the decimal number 2635 to binary: Divide the number repeatedly by 2, keeping track of each remainder, until we get a quotient that is equal to 0:
2635 ÷ 2 = 1317 + 1;
1317 ÷ 2 = 658 + 1;
658 ÷ 2 = 329 + 0;
329 ÷ 2 = 164 + 1;
164 ÷ 2 = 82 + 0;
82 ÷ 2 = 41 + 0;
41 ÷ 2 = 20 + 1;
20 ÷ 2 = 10 + 0;
10 ÷ 2 = 5 + 0;
5 ÷ 2 = 2 + 1;
2 ÷ 2 = 1 + 0;
1 ÷ 2 = 0 + 1;
Now, construct the integer part base 2 representation, by taking the remainders starting from the bottom of the list:
2635₁₀ = 101001001011₂
Answer:
myScore Scores[24]
Explanation:
The array is used to store the data in continuous memory location.
The index of array start from zero, it means first element store in the index zero and second element store in the index 1. So, the index at which the element store is less than 1 from the number of element.
so, the last element is 25 - 1=24.
Option A: myScores + 25
It is not the correct way to store the element.
Option B: myScore Scores[24]
it is the correct form and also the index location is correct.
Option C: myScore Scores[25)
index number is wrong and also the bracket is wrong, it must be [ ].
Option D: myScore== Score[last]
It is not the correct way to store the element.
There, the correct option is B.
Answer:
Here are the for loop for the given question.
for (i = 0; i < NUM_VALS; i++) // for loop
{
/* check if the value of i is equal to NUM_VALS or not.If it is
equal then just print the value without comma.*/
if(i==(NUM_VALS-1)) // if block
System.out.print(hourlyTemp[i]);
/* if i is not equal then just print the value with comma.*/
else // else block
System.out.print(hourlyTemp[i] + ", ");
}
Explanation:
In this we iterating the for loop and check the condition
check if the value of i is equal to NUM_VALS or not.If it is equal then just print the value without comma
If i is not equal then just print the value with comma .
Output:
90,92,94,95
Answer: c) Connection power
Explanation:
Connection power is the power that is established personally in the field of business.A person having connection with powerful person personally outside or inside the organizational field then he/she can attain the desired goals or result through connecting with them, influencing powerful person's decision, getting their things done etc .
- Other options are incorrect because association power, information power,coercive power and referent power are the power to establish connection organization to achieved aim.
- Thus, the correct option is option(c)
Ikev2 requires the use of authentication protocol called Extensible Authentication Protocol (EAP). It is <span>is a protocol for wireless networks that ampiflies on the authentication methods for the Point-to-Point Protocol (PPP).</span>
