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Black_prince [1.1K]
4 years ago
7

A meeting lasted from 11:15 am until 1:00 pm. how long was the meeting?

Mathematics
1 answer:
Evgen [1.6K]4 years ago
8 0
<span>A meeting lasted from 11:15 am until 1:00 pm. how long was the meeting?
We have 1:00 pm= 13.00
13.00-11.15= 1.45
The meeting was 1 hour and 45 minutes</span>
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Round 5.852 to the nearest whole number.
bonufazy [111]

Answer:

6

Step-by-step explanation:

3 0
3 years ago
Can you help me solve these questions....please and thank you!
FromTheMoon [43]
42)
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F. 3

35)
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5 0
4 years ago
A 12-foot by 15-foot patio is increased by placing a stone border around the patio. The width of the border is the same all arou
Arisa [49]

Complete question :

A 12-foot by 15-foot patio is increased by placing a stone border around the patio. The width of the border is the same all around the patio.The perimeter of the patio after it is expanded is 74 feet. The equation which represents x, the width of the border is 2[(12+2x)+15+2x)]=74. What is the width of the border?

1) 2 1/2 feet

2) 3 feet

4) 5 feet

5) 8 1/2 feet

Answer:

2.5

Step-by-step explanation:

Solving for X in the perimeter equation :

2[(12+2x)+15+2x)]=74

Open the bracket

2[(12 + 2x + 15 + 2x)] = 74

2(27 + 4x) = 74

54 + 8x = 74

8x = 74 - 54

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x = 20/8

x = 2.5

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5 0
3 years ago
Find the distance between (-3, 3) and (-3, -3).
Trava [24]

Answer:

6

Step-by-step explanation:

Since the  x coordinate is the same, we only have to look at the y coordinate

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The distance is 6

7 0
3 years ago
Read 2 more answers
The lengths of nails produced in a factory are normally distributed with a mean of 4.84 centimeters and a standard deviation of
Helga [31]

Answer:

Top 3%: 4.934 cm

Bottom 3%: 4.746 cm

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 4.84, \sigma = 0.05

Top 3%

Value of Z when Z has a pvalue of 1 - 0.03 = 0.97. So X when Z = 1.88.

Z = \frac{X - \mu}{\sigma}

1.88 = \frac{X - 4.84}{0.05}

X - 4.84 = 0.05*1.88

X = 4.934

Bottom 3%

Value of Z when Z has a pvalue of 0.03. So X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 4.84}{0.05}

X - 4.84 = 0.05*(-1.88)

X = 4.746

8 0
3 years ago
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