There is no illustration, so it is impossible to answer this question. I apologise.
Answer:
A)

B)

C)

Step-by-step explanation:
We are given the function:

A)
Given that h(1) = 20, we want to find <em>k</em>.
h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

Simplify:

Anything raised to zero (except for zero) is one. Therefore:

B)
Given that h(1) = 40, we want to find 2<em>k</em> + 1.
Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

Simplify:

We can take the natural log of both sides:

By definition, ln(e) = 1. Hence:

Therefore:

C)
Given that h(1) = 10, we want to find <em>k</em> - 3.
Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

Simplfy:

Take the natural log of both sides:

Therefore:

Therefore:

Answer:
x=2
TU:4(2)-1=7
UB: 3
TB: 10
Step-by-step explanation:
4x-1+2x-1=5x
6x-2=5x
6x=5x+2
subtract 5x from both sides
x=2
TU: (4x-1)
4(2)-1
8-1
7
TU:4(2)-1=7
UB: (2x-1)
2(2)-1
4-1
3
UB: 3
TB: 5(2)
TB: 10
<h3>(3x-2)(2x²+x+5)</h3><h3>3x (2x²+x+5) -2 (2x²+x+5)</h3><h3>6x³+3x²+15x-4x²-2x-10</h3><h3>6x³+3x²-4x²+15x-2x-10</h3><h3>6x³-x²+13x-10</h3><h3>this is the answer may u like it and hope full it will be the correct</h3>
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