The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer: x = 2 degrees Fahrenheit
Step-by-step explanation:
5-3= 2 it’s a pretty simple equation
V = 60 as the triangle is looking like a equilateral triangle
Answer:
The eighteenth term is B
Step-by-step explanation:
I could just write the pattern A B A C out until you get to the eighteenth term
A(1) B(2) A(3) C(4) A(5) B(6) A(7) C(8) A(9) B(10) A(11) C(12) A(13) B(14) A(15) C(16) A(17) B(18)
Solve for x:
x + (x + 2) + (x + 4) = 27
3x + 6 = 27
3x = 27 - 6
3x = 21
3x / 3 = 21 / 3
x = 7
The integers:
x + (x + 2) + (x + 4) = 27
7 + (7 + 2) + (7 + 4) = 27
7 + 9 + 11 = 27
27 = 27
The integers are 7, 9 , 11
