Use "PEMDAS"
First we'll add then subtract


<h2>1) Plants</h2><h2>2) Animals</h2><h2>3) Humans</h2>
First thing to do is solve the given equation for v
-11v-7 = 4
-11v = 4+7
-11v = 11
v = 11/(-11)
v = -1
Once we know this, we can use it to compute the following
7v-10 = 7*(-1) - 10 = -7 - 10 = -17
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Answer: -17
To get the solution, we are looking for, we need to point out what we know.
1. We assume, that the number 45.5 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 45.5 is 100%, so we can write it down as 45.5=100%.
4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.
5. Now we have two simple equations:
1) 45.5=100%
2) x=6.81%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
45.5/x=100%/6.81%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 6.81% of 45.5
45.5/x=100/6.81
(45.5/x)*x=(100/6.81)*x - we multiply both sides of the equation by x
45.5=14.684287812041*x - we divide both sides of the equation by (14.684287812041) to get x
45.5/14.684287812041=x
3.09855=x
x=3.09855
now we have:
6.81% of 45.5=3.09855
Hope this helps!
Answer:
Yes, the random conditions are met
Step-by-step explanation:
From the question, np^ = 32 and n(1 − p^) = 18.
Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.
Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.
Confidence interval approach is valid if;
1) sample is a simple random sample
2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.
These two conditions are met by the sample described in the question.
So, Yes, the random conditions are met.