4 fair coins are tossed. What is the probability that all the outcomes are heads?

If a₁ = 4 and an = 5an-1 then find the value of a5.

igor_vitrenko [27]

The value of $a_{5}$ is 2500, when $a_{1}=4$ and $5a_{n-1}$ .

Given that, $a_{1}=4$ and $5a_{n-1}$ .

We need to find the value of $a_{5}$ .

<h3>What is an arithmetic sequence?</h3>

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

Now, to find the value of $a_{5}$ :

$a_{2} =5a_{2-1}=5a_{1}=5 \times4=20$

$a_{3} =5a_{3-1}=5a_{2}=5 \times20=100$

$a_{4} =5a_{4-1}=5a_{3}=5 \times100=500$

$a_{5} =5a_{5-1}=5a_{4}=5 \times500=2500$

Therefore, the value of $a_{5}$ is 2500.

To learn more about arithmetic sequence visit:

brainly.com/question/15412619.

#SPJ1

5 0

2 years ago

Wat does 5 represent in 4c+5=27

svet-max [94.6K]

Answer:

Number? xd

The question is incomplete

Step-by-step explanation:

6 0

3 years ago

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PLEASE HELP PLEASE WILL GIVE BRAINLIEST !!!!! Freya is training for a track race. She starts by sprinting 200 yards. She gradual

DedPeter [7]

Answer:

A. $a_n=200+(n-1)5$

Step-by-step explanation:

Given,

The initial sprinting of Freya = 200 yards,

Also, She gradually increases her distance by 5 yards per day,

So, in second day her sprinting = 200 + 5 = 205 yards,

In third day = 205 + 5 = 210 yards,

In fourth day = 210 + 5 = 215 yards,

...................., so on,.....

Hence, the sequence that shows the given situation,

200, 205, 210, 215, .........

Which is an A.P.

That having first term, a = 200,

Common difference, d = 5,

Thus, the explicit formula for the given situation is,

$a_n=a+(n-1)d$

$\implies a_n=200+(n-1)5$

Option A is correct.

7 0

3 years ago

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Se golpea (chuta) un balón sobre el piso y sale dando botes parabólicos cada vez menores. Si se lanzo inicialmente con una veloc

Ipatiy [6.2K]

Answer:

a)d = 180,91 m

b)t = 11,76 seg

Step-by-step explanation:

Para el lanzamiento de proyectil, la ecuación que nos da la velocidad en V(y) es:

V(y) = Voy - g*t

en donde Voy = Vo * senα ( donde Vo es la velocidad inicial, α el angulo del disparo.

Si en esta ecuación hacemos V(y) = 0 estamos en el punto donde el componente en el eje y de la velocidad del proyectil es cero, ese punto es el punto medio del recorrido.

0 = Vo*sen 60⁰ - g*t

g*t = Vo* √3/2

t = { 32 [m/s] * √3 }2*9,8 [m/s²]

t = 16*√3 / 9,8

t = 2,8278 seg

El tiempo total del primer recorrido es entonces por simetría

t₁ = 2 * 2,8278 t₁ = 5,6556 seg

La distancia del primer impacto al suelo es:

x = Vox * t₁ ( Vox es constante Vx = Vo*cos 60⁰ )

x = 32 * (1/2) * 5,6556

x₁ = 90,49 m

Aplicando los mismos criterios ahora para el segundo bote

Ahora Vo = 32 - 32*(1/4)

V = 24 m/s

g*t = 24 * sen 50⁰

t = 24* 0,7660/ 9,8

t = 1,8759

2*t = 2*1,8759

t₂ = 3,7518 seg

x₂ = Vox * t₂

x₂ = 24* 0,6428*3,7518

x₂ = 57,88 m

Y para el tercer bote Vo = 24 - 24(1/4) Vo = 18 m/s α = 40⁰

t = 18 *0,6428/9,8

t = 1,18

2t = t₃ = 2*1,18

t₃ = 2,36 seg

x₃ = Vox * 2,36 Vox = Vo*cos 40 Vox = 18*0,7660

Vox = 13,79

x₃ = 13,79*2,36

x₃ = 32,54 m

La distancia total será

d = x₁ + x₂ + x₃

d = 90,49 + 57,88 + 32,54

d = 180,91 m

y el tiempo total será la suma de los tiempos

t = t₁ + t₂ + t₃

t = 5,65 + 3,75 + 2,36

t = 11,76 seg

8 0

3 years ago

Please solve, -7x+8=-4(x+1)

omeli [17]

Answer: $x=4$

Simplify both sides of the equation.

$-7x+8=-4(x+1)\\-7x+8=(-4)(x)+(-4)(1)(Distribute)\\-7x+8=-4x+-4$

Add 4x to both sides

$-7x+8+4x=-4x-4+4x\\-3x+8=-4$

Subtract 8 from both sides

$-3x+8-8=-4-8\\-3x=-12$

Divide both sides by -3

$-3x/-3=-12/-3\\x=4$

5 0

3 years ago

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