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Zanzabum
3 years ago
10

19.25 rounded to the near ones

Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0
The answer for rounding 19.25 to the nearest ones place is 19.
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Gabriel is making a mixture of compost and soil to use for a special plant. He wants his final mixture to be 2 parts compost to
ICE Princess25 [194]
2parts compost and 10pats potting soil
2/10=1/5 which is 1 to 5 ratio.
He wants to end up with 6 kilograms which is 1 kg compost and 5kg of plotting soil.so he can use 1 kg compost
hope it helps


4 0
3 years ago
If f(x) = 5x + 4, which of the following is the inverse of Ax)?
Levart [38]

Answer:

f^{-1} (x) = \frac{x-4}{5}

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = 5x + 4 ( subtract 4 from both sides )

y - 4 = 5x ( divide both sides by 5 )

\frac{y-4}{5} = x

change x to f^{-1}(x) and y back to x, thus

f^{-1}(x) = \frac{x-4}{5}

6 0
4 years ago
Can someone help me please!
Hatshy [7]
So we’re looking how many combinations we can make by selecting 5 items in a group of 17.

So we use n C r.

Where I the number of combinations of n objects taken r at a time.

So, 17 C 5

17! / (17-5)! 5! = 6188

(I hope this is correct)
3 0
3 years ago
The green triangle is a dilation of the red triangle with a scale factor of s=13 and the center of dilation is at the point (4,2
Arada [10]

Given:

Scale factor s=\dfrac{1}{3}

Center of dilation = (4,2)

To find:

The coordinates of the points C' and A.

Solution:

We know that, if a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

The scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Suppose the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using rule (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Hence, the coordinates of Point C' are C'(2,5).

Let us assume that point A is A(m,n).

Using rule (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

4 0
3 years ago
Find the missing number<br>86, 47, 75, 48-16<br><br>97, 47, 82, 63-?​
Sergio039 [100]

Answer:

the missing number is 34 because they was going in a pattern

Step-by-step explanation:

7 0
3 years ago
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