All categories

3 years ago

Can someone help me please!

Mathematics

1 answer:

Hatshy [7]3 years ago

3 0

So we’re looking how many combinations we can make by selecting 5 items in a group of 17.

So we use n C r.

Where I the number of combinations of n objects taken r at a time.

So, 17 C 5

17! / (17-5)! 5! = 6188

(I hope this is correct)

You might be interested in

Can someone please send the answers to these questions with explanation? (Attachment) (30 POINTS)

Leto [7]

Answer:

Step-by-step explanation:

a) this graph is that of a parabola that opens up. As is the case for all parabolas, the domain is the set of all real numbers. The range begins with the smallest y-value, which is -4, extending upwards from there: [-4, infinity)

b) this graph's shape most closely resembles that of a polynomial; as we move from left to right, y increases, reaches a local maximum, decreases to a local minimum, and then continues to increase with x. As is the case for all polynomials, the domain is the set of all real numbers. As we move from x = 0 to the left, y decreases without bound; from x ≥ 12 onward, y increases without bound; thus, the range is (-infinity, +infinity).

c) The graph represents a quarter of an ellipse for which x begins at -40 and ends at [4, -16]. Thus, the domain is [-40, 4]. By inspection we see that the smallest y value is -16 and the largest is 4; thus, the range is [-40, 4].

8 0

1 year ago

HELP!!!!!!!!!! 19POINTS!!!!!!!!!!!!!!!!!!

Juli2301 [7.4K]

F(x) = (-1)^x* 2^(2x-1)

5 0

2 years ago

513 is 114% of what number<br>

Liono4ka [1.6K]

Answer:

450

Step-by-step explanation:

513÷114=4.5 then move decimal 2 places to the right

513÷450= 1.14 then move decimal 2 places to the right

6 0

2 years ago

Read 2 more answers

What is the answer to 56/-8?

mina [271]

Answer:

-7

Step-by-step explanation:

5 0

3 years ago

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

2 years ago