Each van carries 13 students and each bus carries 25 students.
<h3><u>Distribution</u></h3>
Given that the senior class at High School A and the senior class at High School B both planned trips to Yellowstone, and the senior class at High School A rented and filled 5 vans and 2 buses with 115 students, while High School B rented and filled 1 van and 6 buses with 163 students, and each van carried the same number of students and each bus carried the same number of students, to determine the number of students in each van and in each bus, the following calculation must be made:
- 5X + 2Y = 115
- 1X + 6Y = 163
- 5X + 2Y = 115
- 5X + 30Y = 815
- 815 - 115 = 28Y
- 700 = 28Y
- Y = 700 / 28
- y = 25
- 1X + 6x25 = 163
- 1X = 163 - 150
- X = 13
Therefore, each van carries 13 students and each bus carries 25 students.
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Answer:
y=0x+-6
Step-by-step explanation:
y=mx+b
Answer:
39,000,000
Roundend to the nearest 1,000,000 or
the Millions Place.
38,802,500.0000000
Roundend to the nearest 0.0000001 or
the Ten Millionths Place.
Answer:
$109 and 35%
Step-by-step explanation:
49.05 is the sale price and the discount is 55%. What’s the original price?
price/ 1- discount
49.05/ 1 - 0.55
49.05/ 0.45
109
for the other part
to find the discount subtract final price from original price
94 - 61.10 = 32.9
Which would be 35% in percent form.
OptionAStep-by-step explanation:95% confidence interval is obtained using the following formulaCOnfidence interval lower bound = mean - critical value * sigma/sq rt nand upper bound = mean + critical value*sigma/sq rt nThus margin of error = critical value*sigma/rt nvaries indirectly as n provided others are remaining the same.Hence lower sample indicates higher margin of errorOut of 4 options given we find that 1 option has maximum margin of error as 21%Hence option. A is most likely coming from a small sample.
