Answer:
1. distance = sqrt( (7-7)^2+(2- -8)^2) = 10
2. check out desk (0,0 ) => distance = sqrt( (0- -9)^2+(0-0)^2) = 9
3. last corner ( -3, 4)
4. area = sqrt( (-10- -10)^2+(10-4)^2) x sqrt( (-3- -10)^2+(10-10)^2) = 6x7 =42
5. check desk (0,0), south direction = negative y axis => P_beginning (0,-20), P_end (0,-(20+25)) = (0,-45)
6. A(-2,-1) and B(4,-1) lie in y =-1. AB = sqrt( (-2- 4)^2+(-1- -1)^2) =6
=> area = 3.6x6 =21.6
=> peri = 2x(3.6+6) = 19.2
7. A(-5,4) and B(2,4), AB = sqrt( (-5- 2)^2+(4- -4)^2) = 7 => AB is base
=> p = peri = 7+ 8.3x2 = 23.6
=> area = sqrt[px(p-7)x(p-8.3)x(p-8.3)]
=sqrt[23.6x(23.6-7)x(23.6-8.3)x(23.6-8.3)] = 302.8
Answer:
I believe the answer is D.
Step-by-step explanation:
Answer:
y=-3x+2
Step-by-step explanation:
Slope-intercept form is given by the equation y=mx+b, where m is defined as the slope and b is defined as the y-intercept (the value on the y-axis that the line crosses). First we can determine the slope by using the slope formula.
m=(y2-y1)/(x2-x1), given two points (x1, y1) and (x2, y2). Keep in mind you can choose which point is (x1,y1) and which is (x2,y2) as long as you are consistent.
Plugging in for (-1,5) and (1,-1), you will get:
m=(-1-5)/(1-(-1))=-6/2=-3
Next, we need to find the y-intercept. For this problem, you can determine it is 2 by looking at the graph of the line. We now have both components to create the slope-intercept form.
m=-3, b=2
y=-3x+2
