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Ray Of Light [21]
3 years ago
8

What is the value of y?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
3 0
Find TU with Pythagorean theorem:
TU=√6²-3²=√36-9=√27=3√3
Now you can find y:
y=√TU²+9²=√27+81=√108=6√3
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Consider the line y = x – 4. A line parallel to the graph of the line would have a slope of . A line perpendicular to the graph
kotykmax [81]

Answer:

A. 1

B. -1.

Step-by-step explanation:

We have been given an equation of a line y=x-4.

A. We know that slope of parallel lines is always equal,

We can see that slope of our given line is 1, therefore the slope of the line parallel to our given line would be 1.

B. We know that the product of slopes of two perpendicular lines is -1.

Let m represent slope of perpendicular to our given line, then:

m\times 1=-1

m=-1

Therefore the slope of the line perpendicular to our given line would be -1.

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What’s the answer ?? The triangle says 84 degrees
myrzilka [38]

Answer:

x = 48°

Step-by-step explanation:

x + x + 84° = 180°

2x = 180° - 84°

2x = 96°

x = 96°/2

x = 48°

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Who was the first president of the United States
Phoenix [80]

Answer: George Washington


Step-by-step explanation:


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Of the entering class at a​ college, ​% attended public high​ school, ​% attended private high​ school, and ​% were home schoole
Veronika [31]

Answer:

(a) The probability that the student made the​ Dean's list is 0.1655.

(b) The probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c) The probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

Step-by-step explanation:

The complete question is:

Of the entering class at a college, 71% attended public high school, 21% attended private high school, and 8% were home schooled. Of those who attended public high school, 16% made the Dean's list, 19% of those who attended private high school made the Dean's list, and 15% of those who were home schooled made the Dean's list.

a) Find the probability that the student made the Dean's list.

b) Find the probability that the student came from a private high school, given that the student made the Dean's list.

c) Find the probability that the student was not home schooled, given that the student did not make the Dean's list.

Solution:

Denote the events as follows:

<em>A</em> = a student attended public high school

<em>B</em> = a student attended private high school

<em>C</em> = a student was home schooled

<em>D</em> = a student made the Dean's list

The provided information is as follows:

P (A) = 0.71

P (B) = 0.21

P (C) = 0.08

P (D|A) = 0.16

P (D|B) = 0.19

P (D|C) = 0.15

(a)

The law of total probability states that:

P(X)=\sum\limits_{i} P(X|Y_{i})\cdot P(Y_{i})

Compute the probability that the student made the​ Dean's list as follows:

P(D)=P(D|A)P(A)+P(D|B)P(B)+P(D|C)P(C)

         =(0.16\times 0.71)+(0.19\times 0.21)+(0.15\times 0.08)\\=0.1136+0.0399+0.012\\=0.1655

Thus, the probability that the student made the​ Dean's list is 0.1655.

(b)

Compute the probability that the student came from a private high school, given that the student made the Dean's list as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D)}

             =\frac{0.21\times 0.19}{0.1655}\\\\=0.2410876\\\\\approx 0.2411

Thus, the probability that the student came from a private high school, given that the student made the Dean's list is 0.2411.

(c)

Compute the probability that the student was not home schooled, given that the student did not make the Dean's list as follows:

P(C^{c}|D^{c})=1-P(C|D^{c})

               =1-\frac{P(D^{c}|C)P(C)}{P(D^{c})}\\\\=1-\frac{(1-P(D|C))\times P(C)}{1-P(D)}\\\\=1-\frac{(1-0.15)\times 0.08}{(1-0.1655)}\\\\=1-0.0815\\\\=0.9185

Thus, the probability that the student was not home schooled, given that the student did not make the Dean's list is 0.9185.

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It would just be 2 teaspoons
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