Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
Answer:
Ok
Step-by-step explanation:
I will help you or maybe.
This is a division problem. You can use the standard algorithm of 128/ 5. Or you can create equal groups (draw five circles) and count out eggs until you distribute them all. I would start with 20 in each circle. That would be 20+ 20+ 20+ 20+ 20= 100 Then think 128-100= 28 Next count by 5's. 5+ 5+ 5+ 5+ 5= 25 Then think what is 28-25= 3 so 128/ 5= 25 with a reminder of 3 eggs left over.
Answer:
Step-by-step explanation:
Your exponential formula is in the form y = ab^x. In this form, the coefficient 'a' is the initial value, the y-intercept, the value when x=0. The value 'b' is the growth factor, which is 1 more than the growth rate per increment of x. This problem is asking for the growth rate to be expressed as a percentage.
__
Given p(x) = 78500(1.02^x), we can compare to the exponential function form to see that ...
- a = 78,500
- b = 1.02 = 1 +0.02 = 1 +2%
The value of x is zero in the year 2000, so the population that year is ...
p(0) = a = 78,500
The increase per year is the value of 'b' with 1 subtracted:
growth rate = 2% per year
