Given:
Consider the given expression is
To find:
The radical form of given expression.
Solution:
We have,
![(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}](https://tex.z-dn.net/?f=%284x%5E3y%5E2%29%5E%7B%5Cfrac%7B3%7D%7B10%7D%7D%3D%5Csqrt%5B5%5D%7B2%5E3%7D%5Csqrt%5B10%5D%7Bx%5E9%7D%5Csqrt%5B5%5D%7By%5E3%7D)
![[\because x^{\frac{1}{n}}=\sqrt[n]{x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20x%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%7D%5D)
![(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}](https://tex.z-dn.net/?f=%284x%5E3y%5E2%29%5E%7B%5Cfrac%7B3%7D%7B10%7D%7D%3D%5Csqrt%5B5%5D%7B8y%5E3%7D%5Csqrt%5B10%5D%7Bx%5E9%7D)
Therefore, the required radical form is ![\sqrt[5]{8y^3}\sqrt[10]{x^9}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B8y%5E3%7D%5Csqrt%5B10%5D%7Bx%5E9%7D)
.
Answer:
Step-by-step explanation:
An intercept is where the line hits the axis.
Lets start with x. The x intercept is always going to be what x equals when y = 0. So we know the second value of the x intercept is going to be 0, because the second value is y. The line hits the x axis at -1.2, so the x intercept is -1.2, 0
The y intercept it what y equals when x equals 0. So the first value is going to be 0, to represent x. The line hits the y intercept at the point 0, -0.7.
Answer:
Step-by-step explanation:
one
The only really certain way of getting an odd integer is to do 2k + 1. Therefore the answer should be something like 2k+1, 2k+3, 2k + 5
The best I can do for the first one is to assume that k is odd and that the answer is k + 10, k+12, k+14, but I would ask your instructor if this is merely the best answer out of a poor lot or if the question really has no answer.
Two things should be noted.
1. k has to be odd.
2. The first choice has to give consecutive integers because what is added on is 2 3 and 4. Those numbers are consecutive.
Two
k+1, k+2, k+3. See point 2 above. k is a constant and any number. 1,2,3 are consecutive so the results are consecutive. Even if k < 0 the numbers will be consecutive.
k= - 10
k+1 = - 9
k+2 = -8
k+3 = - 7
These are consecutive.
Your first choice will give either consecutive odd or even numbers depending on what k is.
If k = even, then k+6, k+ 8, k+10 will all be even.
If k = odd then the givens will be odd.
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
Solution:
Let f be the bags of flour and b be the pounds of butter.
Cost of 20 bags of flour 16 pound of butter = 110
⇒ 20f + 16b = 110 -------------------- (1)
Cost of 30 bags of flour 12 pound of butter = 120
⇒ 30f + 12b = 120 -------------------- (2)
Equation (1) and (2) are the system of equations.
(2) ⇒ 30f + 12b = 120
Subtract 30f from both sides.
⇒ 12b = 120 – 30f
Divide by 12 on both sides.
-------------------- (3)
Substitute (3) in (1).
Subtract 160 from both sides.
Divide by –20, we get
f = 2.50
Substitute f = 2.5 in equation (3), we get
b = 3.75
Cost of each bags of flour = $2.50
Cost of each bags of butter = $3.75
10 wins/ 6 losses= 1.667
13 wins/ 7 losses= 1.857..
32 wins/ 18 losses= 1.77..
6 wins/ 3 losses= 2
The last team has the highest win to loss ratio, and therefore has the highest winning percentage.
Final answer: Last team, 6 wins and 3 losses
