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evablogger [386]
3 years ago
11

Leslie says that 5 multiplied by an even number always results in an even product. Is Leslie's statement correct?

Mathematics
2 answers:
djverab [1.8K]3 years ago
5 0
Yes; Leslie is correct. For example,
5•2 = 10
5•4= 20
5• 6= 30
And so on..
Rufina [12.5K]3 years ago
3 0
Yes, Leslie is correct. Two such examples are 5*100, which is 500 (even) and 5*18, which is 90 (also even).
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Steve makes a banner with an area of 8 square feet. On a grid, draw all possible rectangles with an area of 8 square feet and si
Maksim231197 [3]

Answer:

The correct answers are with side lengths 1 feet and 8 feet, the perimeter is 18 feet; and with side lengths 2 feet and 4 feet, the perimeter is 12 feet.

Step-by-step explanation:

The area of a rectangular banner is 8 square feet.

The side lengths of this rectangular banner are whole numbers.

Thus the possible pairs of side lengths that would give 8 when multiplied with each other are (1 , 8) ; (2 , 4).

So the possible side lengths are 1 feet and 8 feet or 2 feet and 4 feet.

The perimeter when the side lengths are 1 feet and 8 feet are 18 feet.

The perimeter when the side lengths are 2 feet and 4 feet are 12 feet.

8 0
3 years ago
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Furkat [3]

you will need to find the area

A=height multiplied by the base divided by 2


4 0
3 years ago
The number of goldfish in a tank is 12, and the volume of the tank is 45 cubic feet. What is the density of the tank?
Lady_Fox [76]

Answer:

0.22

Step-by-step explanation:

In this problem, we divide 12 goldfishes by 45 cubic feet. This is equal to 0.27 goldfish per cubic feet. Answer is A.

0.22

7 0
3 years ago
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There are 2504 computer science students at a school. Of these, 1876 have taken a course in Java, 999 have taken a course in Lin
Y_Kistochka [10]

Answer:

492

Step-by-step explanation:

As per the given data of the question:

Total number of students = 2504

Number of students in Java (J) = 1876

Number of students in Linux (L) = 999

Number of students in C = 345

J∩L = 876

L∩C = 231

C∩J = 290

L∩J∩C = 189

Now according to Venn-diagram as drawn below:

Number of students haven taken courses in Java and Linux both only

= J∩L - L∩J∩C

= 876 - 189

= 687

Number of students haven taken courses in Java and C both only

= C∩J - L∩J∩C

= 290 - 189

= 101

Number of students haven taken courses in C and Linux both only

= L∩C - L∩J∩C

= 231 - 189

= 42

Therefore,

Number of students only in Java = 1876 - 687 - 189 - 101 = 899

Number of students only in Linux = 999 - 687 - 189 - 42 = 81

Number of students only in C = 345 - 42 - 189 - 101 = 13

So,

Number of students who have not taken a course in any of these three subjects

= 2504 - 899 - 81 - 13 - 687 - 189 -101 - 42

= 492

Hence, the students who have not taken a course in any of these three subjects = 492.

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3 years ago
If the unit price of oranges is 0.08 per pound and Jim pays 2.08 how many oranges does he buy
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26 I believe, I'm pretty sure :)
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3 years ago
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