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Lerok [7]
3 years ago
12

9000 for 5 years at 4.5% compounded monthly

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0
I think its 9000(1.045)^5. Hope this helps. That equals $11,215.60, or rounded to the nearest dollar, $11,215.
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Owen grew 5/16 of an inch this year and 3/8 of an inch last year. How much did he grow in two years?
DerKrebs [107]
Owen grew 11/16 in two years.

3/8 = 6/16
6/16 + 5/16 = 11/16

I hope I helped. Brainliest would be appreciated.
3 0
3 years ago
Suppose that X is a random variable with mean 30 and standard deviation 10. Also suppose that Y is a random variable with mean 2
Bas_tet [7]
Part a: For variable X using z score you have (x-30)/10, replace X for this expression in (a), i mean Z=2+10((x-30)/10) = 2+x-30= put this in the way of z score = (x-18)/1, so the mean is 18 and standard deviation is 1.
Part b: Z=X+Y= (x-30)/10 + (x-20)/8 = solve adding fractions = (18x-440)/80 now divide all the numbers between 18 (because you need to show as z score way) = (x-24.4)/4.4, so the mean is 24.4 and standard deviation is 4.4.
For part c,do the same.
3 0
3 years ago
An elementary school is in a growing suburb. The school’s principal estimates that the current enrollment of 750 students will i
HACTEHA [7]

Answer:

62.9% in ten years

Step-by-step explanation:

This type of growth corresponds to what is called an exponential growth, since in the expression for the number of students keep including the multiplication of the same factor as the years go by, Let's start by analyzing what happens the first year:

The initial enrollment of 750 is expected to grow by 5%, therefore after one year the enrollment should be:

After one year = Year_1 = 750 + 5% increase = 750+750*0.05=750(1+0.05)

where we have used the decimal form of 5% as he factor 0.05 multiplying 750 (the initial enrollment) to give the increase.

After the second year, we consider a starting value of Year_1 enrollments that will increase another 5%, which gives: Year_2 = Year_1 + Year_1 * 0.05= Year_1 (1 + 0.05).

So replacing Year_1 by its original expression (750(1+0.05)) we notice that Year_2 = 750 * (1+0.05) * (1+0.05) = 750 * (1+0.05)^2

We can go on with this same reasoning and find that each year includes a new factor (1+0.05) to the new increasing enrollment.

At the end of 10 years, the number of enrollment will be:

750*(1+0.05)^10=1221.67

which we can round to 1222 students enrolled

This means and increase of: \frac{1222-750}{750} =0.62933

That is approximately 62.9%

6 0
3 years ago
the graph y= |x| is shifted up by 7 units and to the left 8 units. what is the equation of the new graph?
Marta_Voda [28]
<h3>Answer:</h3>

\large\boxed{y= |x+8| +7}

<h3>Step-by-step explanation:</h3>

in this question, we're trying to find the equation of the new graph.

We know that:

  • The current equation is y= |x|
  • It is shifted up by 7 units
  • Moves to the left by 8 units

With the information above, we can solve the question.

When we shift something up, we would represent it as our "y" variable", due to the fact that it doesn't intervene with x or the x axis.

Your equation should currently look like this:

y= |x| + 7

We also know that the equation moves to the left 8 times.

This is related to the x axis, so we would change what's inside the absolute value.

We know that if is shifted left, we would add. Therefore, we would add 8 inside the absolute value.

Your equation should look like this:

y= |x + 8| + 7

Your final equation should be y= |x + 8| + 7

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
6 0
3 years ago
What is the product of 8/15 times 6/5 and 1/3
nordsb [41]
The answer would be 16/75
3 0
3 years ago
Read 2 more answers
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