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Levart [38]
4 years ago
6

Machine part A must always be four inches smaller in diameter than machine part B's diameter. If machine part A's diameter is 16

inches and machine part B's diameter is x inches, which of the following can be used to solve for x?
A. 16=4X
B. 16=X - 4
C. 16=X+4
D. 16=X/4
     Please help me with this thank you.
Mathematics
1 answer:
leva [86]4 years ago
3 0
B. 16 = x - 4. this relation is true!
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Can you help me with this question please
solniwko [45]

Answer:

the answer is 9^8

Step-by-step explanation:

9^3 * 9^5 = 9^ 3 + 5 = 9^8

7 0
3 years ago
I need help.please ​
DedPeter [7]

Answer:

1. cos = adjacent / hypotenuse

tan = opposite / adjacent

sin = opposite / hypotenuse

2. cos = adjacent / hypotenuse

cos(G) = 429/821 = 0.5225 ≈ 0.523

tan = opposite / adjacent

tan(G) = 700/429 = 1.6317 ≈ 1.632

sin = opposite / hypotenuse

sin(G) = 700/821 = 0.8526 ≈ 0.853

3. Part A:

sin(G) = opp / hyp = 420/427 = 0.9836 ≈ 0.984

Part B:

tan(Z) = opp / adj = 77 / 420 = 0.1833 ≈ 0.183

Part C:

cos(Z) = adj / hyp = 420 / 427 = 0.9836 ≈ 0.984

Part D:

sin(M) = opp / hyp = 427 / 427 = 1

Part E:

The sine value of any right angle is 1. The opposite side to the right angle is the hypotenuse.

Explanation:

1. Use "SohCahToa" to remember the equations.

S = o/h         C = a/h       T = o/a

"o" for opposite; "h" for hypotenuse; "a" for adjacent

"S" is sine; "C" is cosine; "T" is tangent.

2. Use the formulas for sin, cos and tan. Substitute the numbers for each side into the equations.

Since the values depend on ∠G, ∠G determines which side is opposite or adjacent. The adjacent side touches ∠G but the opposite side does not. The hypotenuse is the longest side.

3. Use the sin, cos and tan formulas from question 1. Which side is called opposite or adjacent depends on which angle (G, Z or M).

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3 years ago
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sergejj [24]
I have no clue sorry
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3 years ago
Match each linear equation to the appropriate description: Column A 1. : 2. : 3. : 4. : Column B a. A linear equation with slope
timama [110]
<span>b. A linear equation with slope 5 and y-intercept 1 c. A linear equation with slope 2 and y-intercept 3 d. A linear equation with slope 3 and y-intercept 2

</span>
4 0
3 years ago
Read 2 more answers
Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose
Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

In which

x is the number of sucesses

&#10;e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson mean:

\mu = 0.2

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164&#10;

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819

P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164&#10;

P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so p = 0.181

We want to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671

0.671 = 67.1% probability that neither contains a missing pulse

8 0
3 years ago
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