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Helen [10]
3 years ago
14

Please, I need it ASAP!!!! I will give brainliest if correct!!!

Mathematics
1 answer:
LenKa [72]3 years ago
4 0

Answer:

recursive: f(0) = 7; f(n) = f(n-1) -8

explicit: f(n) = 7 -8n

Step-by-step explanation:

The sequence is an arithmetic sequence with first term 7 and common difference -8. Since you're numbering the terms starting with n=0, the generic case will be ...

recursive: f(0) = first term; f(n) = f(n-1) + common difference

explicit: f(n) = first term + n·(common difference)

To get the answer above, fill in the first term and common difference values.

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2. Place the origin over the center point, or vertex, of the angle you want to measure. The small hole in the middle of the protractor is the origin. Put the vertex of the angle with the center of the cross in the origin.

3. Rotate the protractor to line up one leg of the angle with the baseline. Maintain the vertex of the angle in the origin and rotate the protractor so that one of the legs of the angle falls on the baseline of the protractor.<span>The baseline is even to the edge, but is not the flat edge of the protractor. It is lined up with the center of the origin and the line projects to the start of the scale on either side.

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7 0
3 years ago
What is the factored form of 5x+x^2=0
Colt1911 [192]
5x+x^2=0\\ \\x(5+x)=0\\ \\x=0 \ \vee \ 5+x=0 \\\\ x=0 \ \vee \ x=-5


3 0
3 years ago
Attached below...………………………...tec
r-ruslan [8.4K]

Answer:

1\sqrt{3}

Step-by-step explanation:

This is the answer because in a 30-60-90 triangle each side has a different formula to find it, the side across from angle 60 is half the hypotenuse and root 3

4 0
3 years ago
Read 2 more answers
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Answer:

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3 years ago
Of 580580 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compa
Lubov Fominskaja [6]

Answer:

a) The 99% confidence interval would be given (0.204;0.296).

b) We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

c) No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

Step-by-step explanation:

Part a

Data given and notation  

n=580 represent the random sample taken    

X represent the seafood sold in the country that is mislabeled or misidentified by the people

\hat p=0.25 estimated proportion of seafood sold in the country that is mislabeled or misidentified by the people

\alpha=0.01 represent the significance level (no given, but is assumed)    

p= population proportion of seafood sold in the country that is mislabeled or misidentified by the people

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.25 - 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.204

0.25 + 2.58 \sqrt{\frac{0.25(1-0.25)}{580}}=0.296

And the 99% confidence interval would be given (0.204;0.296).

Part b

We have 99% of confidence that the true population proportion of all seafood sold in the country that is mislabeled or misidentified is between (0.204;0.296).  

Part c

A government spokesperson claimed that the sample size was too​ small, relative to the billions of pieces of seafood sold each​ year, to generalize. Is this criticism​ valid?

No that's not true. Because the necessary assumptions and conditions for the confidence interval for the proportion are satisifed, so then we can use inferential statistics to interpret the interval to the population of interest.

4 0
4 years ago
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