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3 years ago

Please, I need it ASAP!!!! I will give brainliest if correct!!!

Mathematics

1 answer:

LenKa [72]3 years ago

4 0

Answer:

recursive: f(0) = 7; f(n) = f(n-1) -8

explicit: f(n) = 7 -8n

Step-by-step explanation:

The sequence is an arithmetic sequence with first term 7 and common difference -8. Since you're numbering the terms starting with n=0, the generic case will be ...

recursive: f(0) = first term; f(n) = f(n-1) + common difference

explicit: f(n) = first term + n·(common difference)

To get the answer above, fill in the first term and common difference values.

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3 years ago

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3 years ago

Combine like terms to create an equivalent expression. 2(1/5m - 2/5) + 3/5

Alexus [3.1K]

Answer:

$\dfrac{2}{5}m-\dfrac{1}{5}$

Step-by-step explanation:

First, use the distributive property $a\cdot (b-c)=a\cdot b-a\cdot c.$ Thus,

$2\cdot \left(\dfrac{1}{5}m-\dfrac{2}{5}\right)=2\cdot \dfrac{1}{5}m-2\cdot \dfrac{2}{5}=\dfrac{2}{5}m-\dfrac{4}{5}.$

Then given expression will take look

$\dfrac{2}{5}m-\dfrac{4}{5}+\dfrac{3}{5}.$

This expression consists of three terms, one term with m and two terms without m. Combine terms without m:

$-\dfrac{4}{5}+\dfrac{3}{5}=-\dfrac{1}{5}.$

Therefore, an equivalent expression is

$\dfrac{2}{5}m-\dfrac{1}{5}.$

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3 years ago

Read 2 more answers

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3 years ago

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3 years ago