Answer:

Minimum 200 people other than the 2 charity representatives.
Step-by-step explanation:
Given that:
The venue can hold a maximum of 500 people.
Cost of venue = $1000
Per person cost for food = $20
Two charity representatives get to attend the dinner for free.
To find:
The inequality and to determine how many people must come to keep costs at most $25.
Solution:
Let the number of people attending the dinner = 
Cost of food for
people = 
Total cost = $1000 + 
Cost per person = Total cost divided by Number of people attending the dinner.
As per question statement:

Therefore, the answer is:
Minimum 200 people other than the 2 charity representatives should attend the dinner.
Answer:
25x-49
Step-by-step explanation:
5x×5x=25x 5x×-7= -35x
7×5x=35x 7×-7=-49
(combine like terms)25x+-35x+35x= 25
hope that helped you!
It’s either 40 or 5 games because it says that each team will play every other team once
Pretty sure it’s y= 5 + 1.95x
I don’t think that the number of people matters because the cost doesn’t vary based on the number of people
You could say that a(n) = 12 - 5n .
Then ...
a(1) = 12 - 5 = 7
a(2) = 12 - 10 = 2
a(3) = 12 - 15 = -3
and so on.
So it seems to work.