Answer:
Step-by-step explanation:
By applying Pythagoras theorem in ΔEGD,
ED² = EG² + GD²
y² = 5² + 2²
y = √29
y = 5.39
By applying cosine rule in ΔBCD,
cos(28.3)° = 
x = 19cos(28.3)
x = 16.73"
Area of ABCDE = Area of trapezoid ABDE + Area of triangle BCD
= 
= 85 + 75.28
= 160.28 square inch
Perimeter of ABCDE = AB + BC + CD + DE + AE
= 5.39 + 16.73 + 9 + 5.39 + 15
= 51.51"
Answer:
4 units to the right :)
Step-by-step explanation:
-1 plus 4 equals 3. and x is from left to right and y stayed the same soooo
Answer:
Step-by-step explanation:
Remark
The diagram is a mess of lines; you have to guess where that 12 belongs. Just to make the question a bit more interesting, I'm going to say the 12 belongs to the perpendicular.
If that's true you can find KT using Pythagorus. KT and RT are equal. (SSS)
So, let's go.
Givens
1/2 of ST = 1/2 32 = 16
12 is the leg of the small triangle KT and the third point where the perpenduclar line meets ST.
Solution
KT^2 = 16^2 + 12^2
KT^2 = 256 + 144
KT^2 = 400
KT = sqrt(400)
KT = 20
RK = KT because parts of a congruent triangle = parts of the other triangle containing the line (KT) that you are trying to find the length of.
Hello!
Let's write this as an equation below.
310/3+d=295/d
As you can see, we can cross-multiply this proportion giving us the equation below.
310d=295(3+d)
310d= 295d+885
Now, we subtract 295d from both sides.
15d=885
Now we divide both sides of the equation by 15.
d=59
Therefore, Dana travels 59 mph.
I hope this helps!
Answer:A
Step-by-step explanation: because there is an association with the child’s hight and age so the answer is A ( plus I have did this before and got it wrong and the actual Answer was A when I picked B
