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Delicious77 [7]
3 years ago
5

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics
1 answer:
viktelen [127]3 years ago
3 0

Answer:

Degree:3

Y-intercept:-6

Step-by-step explanation:

The given function is:

f(x) =  -  {(x  + 1)}^{2}( {2x - 3)}(x +2 )

To find the degree, we multiply out the leading terms of each factor.

The leading term of the first factor is:

-  {x}^{2}

and that of the second factor is

2x

and the third one is:

x

If we multiply out the leading terms, we would get:

-  {x}^{2}  \times 2x \times x =  - 2 {x}^{3}

Therefore the degree of the function is:

3

To find the y-intercept, we put x=0 to get:

f(0) =  -  {(0  + 1)}^{2}( {2 \times 0 - 3)}(0 +2 )

\implies \: f(0) = ( 1)( - 3) \times (2) =  - 6

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A car can travel 3/4 of a mile in 1/30 of an hour. What is the car’s speed in miles per hour?
IceJOKER [234]

Answer:

3.0 Miles per hour

Step-by-step explanation:

https://www.countcalculate.com/cars-and-speed/average-speed/result?r=jfqffaktat

3 0
3 years ago
Write an equation in point-slope form of the line through these given points.I need separate answers for each problem, thx
andrew-mc [135]

I like point point form because it doesn't fail in the no slope case.  The line through (a,b) and (c,d) is

(c-a)(y-b) = (d-b)(x-a)

Point slope form is almost the same,

y - b = \dfrac{d-b}{c-a} (x-a)

1. (a,b)=(4,0),(c,d)=(-2,1)

y - 0 = (1 - 0)/(-2 - 4) (x - 4)

Answer: y = (-1/6)(x-4)

2.

y - -2 = (3 - -2)/(5 - -3) (x - -3)

Answer: y + 2 = (5/8) (x+3)

3.

y - 1 = (4 - 1)/(3 - -5) (x - -5)

Answer: y - 1 = (3/8) (x+5)

7 0
3 years ago
Help please!!!!!!!!!!!!!
dedylja [7]

Answer:

position         1             5             8                12               19             25

term              -8            8             20             36               64            88

Step-by-step explanation:

(n - 1) is position ( n ∈ N)

d is the distance between the numbers in the sequence

a1 is the first number in the sequence

we have the fuction: a(n) = a1 + (n - 1)d

see in the table, with position = 1, term = -8 => a1 + d = -8

                                    position = 25, term = 88 => a1 + 25d = 88

=> we have: a1 + d = -8

                     a1 + 25d = 88

=> a1 = -12

    d = 4

=> a(n) = -12 + 4(n - 1)

=> term = 8, position = (8 + 12)/4 = 5

    position = 8, term = -12 + 4.8 = 20

    term = 36, position = (36 + 12)/4 = 12

    position = 19, term = -12 + 4.19 = 64

5 0
3 years ago
Read 2 more answers
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
12
Papessa [141]

Answer:

42

Step-by-step explanation:

4 0
2 years ago
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