2 years ago

Consider the function f(x)=x(x-4).

Mathematics

1 answer:

alexandr402 [8]2 years ago

5 0

Answer:

(2-c,y)

Step-by-step explanation:

idk this is what algebra nation told me so yeah

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Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

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$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

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Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

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