Question

Heya!

Answer 1

Answer:

See Below.

Step-by-step explanation:

We are given that ABC is a triangle in which AB = AC.

A circle passing through B and C also intersects the sides AB and AC at points D and E respectively.

And we want to prove that AD = AE.

By the secant-secant theorem (shown below), we know that:

$AD(AB)=AE(AC)$

We are given that AB = AC. So, by substitution:

$AD(AB)=AE(AB)$

And by dividing both sides by AB (AB ≠ 0), we acquire:

$AD=AE$

Q.E.D.