Question

What is the value of x in the equation 6(x + 1) – 5x = 8 + 2(x – 1)?

Answer 1

Answer:

$x=0$

Step-by-step explanation:

we have

$6(x+1)-5x=8+2(x-1)$

solve for x

$6x+6-5x=8+2x-2$

Group terms that contain the same variable and move the constants to the other side

$6x-5x-2x=8-2-6$

$-x=8-8$

$x=0$

Answer 2

6(x + 1) - 5x = 8 + 2(x - 1)
6x + 6 - 5x = 8 + 2x - 2
x + 6 = 6 + 2x
0 = x
So, x = 0
Hope this helped!